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Monica [59]
4 years ago
7

You are initially at rest in your car. at time t = 0, a truck passes you moving at 25.0 m/s. you then immediately begin to accel

erate at 3.00 m/s² in the same direction the truck is moving. if you maintain this acceleration, and the truck maintains its speed, when will you overtake the truck?
Physics
1 answer:
WITCHER [35]4 years ago
8 0

Let the car will overtake the truck after time 't'. In this time, the distance cover by the car is equal to the distance cover by the truck.

Distance cover by the truck in time 't' = Speed of the truck× time = 25t m

Distance cover by the car can be calculated using the second equation of motion, that is

s= ut + \frac{1}{2}at^{2}

As, the car started from the rest its initial velocity is zero.

Acceleration of the car= 3 m/s²

∴ Distance cover by the car = 0×t + \frac{1}{2}*3*t^{2}

= \frac{3}{2}t^{2} m

Equating the distances cover by the car and the truck, we get

25t=\frac{3}{2}t^{2}

t=\frac{50}{3} = 16.66 s

Hence, the car will overtake the truck in 16.66 s.

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Length of third side = 3.97m

Explanation:

First of all, let we draw the triangle from the given information assuming our first corner is A. second corner is B and third corner is C.

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From B-C we have distance = 4.3m = Say it a

From A-C we have distance = ? = Say it b which we have to find out.

Using the Law of Cosines: The square of the unknown side equals to the sum of squares of other 2 sides and subtracting 2*(Product of other sides)*(Cos(Angle opposite to the unknown side)

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b² = a² + c² - 2acCos(B)         -  Say it equation 1

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There values are:

a = 4.3m;  c = 5.5m ; Angle B = 0.8 rad = 0.8 * 57.3 = 45.84 degrees where 1 rad = 57.3 degrees

Now by putting the respectve values in equation 1 we have:

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b² = 18.49 + 30.25 - 32.95

b² = 15.79

b  = √15.79

b = 3.97m

Thus the length of third side is 3.97m.

PS: The picture of triangle is being attached for yours understanding.

6 0
3 years ago
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