A bicycle racer is going downhill at 11.0 m/s when, to his horror, one of his 2.25 kg wheels comes off when he is 75.0 m above t
he foot of the hill. We can model the wheel as a thin-walled cylinder 85.0 cm in diameter and neglect the small mass of the spokes. (a) How fast is the wheel moving when it reaches the bottom of hill if it rolled without slipping all the way down? (b) How much total kinetic energy does it have when it reaches bottom of hill?
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<h2>Answer: Pressure</h2>
<u>Pressure</u> is the force exerted by a gas, a liquid or a solid on a surface (or area)
.
Its unit according to the International System of Units is Pascal which is equal to
and its formula is:
Answer:
The smallest radius will be four (4) times the initial radius
Explanation:
The car maintains a constant angular speed. According to Newton's Second Law F = m a
1.
2.
Replacing 2 in 1
3.
Where:
Fr= Frictional force
Rp= Initial Radius
An= Centripetal Acceleration
M= Mass
V= Velocity
Also we have that:
4.
μ= Coefficient of friction between the car and the surface
M= Mass
W= Weight
G= Gravity
r is cleared from equation 3
5.
Replacing 4 in 5
6.
Simplifying
7.
Now we have a new velocity equal to twice the initial velocity, We replace it by 2v in equation 7
8.
Computing
9.
Replacing 5 in 9
