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LiRa [457]
4 years ago
5

You own an electronics store with a merchandise book value of $245,000. You conduct a physical inventory and find the value to b

e $237,000. Your total sales between inventories totaled $360,000. Calculate the shrinkage as a percentage of sales.
Mathematics
2 answers:
malfutka [58]4 years ago
8 0

It is given that the electronics store has a merchandise book value of $245,000. Thus, in other words it's inventory as per records = $245,000 .

Likewise when the conduct of the physical inventory was done it was found to be of the value $237,000. Thus, in other words the inventory as per physical count = $237,000

Therefore, Shrinkage will be: Inventory on record - Inventory as per physical count.

Therefore, Shrinkage = $245,000 – $237,000 = $8,000

Now, Total sales = $360,000

Therefore, Shrinkage as a percentage of sales is given as:

\frac{8000}{36000}\times 100 = 2.22\%

Thus, the shrinkage as a percentage of sales is <u>2.22%</u>.

suter [353]4 years ago
6 0

Answer:

2.2%

Step-by-step explanation:

i just took the quiz

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3 years ago
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Answer:

According to Charles' Law the order of arrangement of the location where the balloon has the smallest size to the location where the balloon has the largest size is given as follows;

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The parameter of the balloon Katie blows are;

The amount of air in the balloon = Fixed (constant)

The initial size of the balloon = The length of the measured string

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The size of the balloon is given by the volume of the balloon

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V ∝ T

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The locations arranged in order of increasing temperature is given as follows;

Freezer < Cold refrigerator < Normal temperature classroom < Warm cupboard

Given that Katie blow's the balloon in a normal temperature classroom, according to Charles Law, we have;

The temperature of the air in the balloon decreases largely in a freezer, therefore, the size of the balloon largely decreases

The temperature of the air in the balloon increases in a warm cupboard, therefore, the size of the balloon increases

The temperature of the air in the balloon decreases slightly in a cold refrigerator, therefore, the size of the balloon decreases

The temperature of the air in the balloon remains the in a normal temperature classroom, therefore, the size of the balloon remains the same

The size of the balloon reduces the most in a freezer

The size of the balloon increases in a warm cupboard

The size of the balloon decreases slightly in a cold refrigerator

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