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Gwar [14]
3 years ago
8

For how many tickets is the cost the same for club members and non-members?

Mathematics
1 answer:
WITCHER [35]3 years ago
3 0
If its a parent then the answer would be 60
You might be interested in
How many groups of 100 can you take out of 941 when diving by 3?
Semenov [28]

Answer:

300 times

Step-by-step explanation:

when you divide 941 by 3, you have to divide it into the hundreds place first.

3 fits into 900 (it's the hundreds place) 300 times

to check:

3 * 300 = 900  

3 0
3 years ago
If two siblings are boys, what is likelihood that the third sibling will also be a boy
melamori03 [73]
The is a 50% chance of being a boy or a girl.....previous siblings do not matter. Every child is an independent event. So even if u had 2 siblings that were boys, the result of the next one being a boy is still gonna be 50%...just as the odds of it being a girl, is 50% as well.
6 0
3 years ago
Read 2 more answers
Pls help thank you so much
Rudik [331]

Answer:

C

Step-by-step explanation:

You can start by "filling up" all of the bigger boxes. 75*14=1050 cupcakes, which when subtracted from the total initial amount leaves 400 cupcakes for the smaller boxes. The smallest multiple of 13 smaller than 400 is 390, which is 10 smaller than 400. Therefore, there will be 10 cupcakes left over, or answer choice C. Hope this helps!

8 0
4 years ago
Read 2 more answers
There are 8 members on a board of directors. if they must form a subcommittee of 6 members, how many different subcommittees are
Shtirlitz [24]
1. Given a group of n people. There are C(n, r) ways of forming groups of r out of n.

2. Where C(n, r)=\frac{n!}{r!(n-r)!}

3. For example, given {Andy, John, Julia}. We want to pick 2 people to give a gift: we can pick {(Andy, John), (Andy, Julia), (John, Julia)}, so there are 3 ways. So we can list and count.

4. Or we could do this with the formula C(3, 2)=\frac{3!}{2!(1)!}= \frac{3*2*1}{2*1}=3

5. C(8, 6)=\frac{8!}{2!6!}= \frac{8*7*6!}{2*6!}= \frac{8*7}{2}= 4*7=28

So there are C(8,6)=28 ways of chosing 6 out of 8 people to form the subcommittees. <span />
5 0
3 years ago
Help me on the last question please asap
bogdanovich [222]
Is the question your asking the one at the bottom
7 0
3 years ago
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