4 years ago

there are 13 boys and 10 girls in a class. work out the total number of ways that 1 boy and 1 girl can be chosen from the class

Mathematics

1 answer:

LuckyWell [14K]4 years ago

4 0

Answer:

130 ways

Step-by-step explanation:

13*10 = 130

130 ways

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------------

I think the question is missing which variable is defined as $=m+3$ , so I will solve for $v=m+3$ since is the only other variable in the equation.

substituting $v=m+3$ into $\frac{6}{7}=\frac{m}{v}$ :

$\frac{6}{7}=\frac{m}{m+3}$

and we solve for m:

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there are 13 boys and 10 girls in a class. work out the total number of ways that 1 boy and 1 girl can be chosen from the class​

there are 13 boys and 10 girls in a class. work out the total number of ways that 1 boy and 1 girl can be chosen from the class