Answer:
9/2
Step-by-step explanation:
(3, -20) & (11, 16)
To find the slope of the line that passes through these points, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)
Plug in these values:
(16 - (-20)) / (11 - 3)
Simplify the parentheses.
= (36) / (8)
Simplify the fraction.
36/8
= 9/2
9/2 is the most simplified fraction. This is your slope.
Hope this helps!
The cost to equip all the stations in the chemistry lab is calculated as: $393.75.
<h3>How to Calculate Total Cost?</h3>
In this scenario, we are given the following:
Total number of stations = 21 stations
Length of rubber tubing each of the stations in the chemistry lab needs = 5 feet
Total length of rubber tubing needed for all stations in the chemistry lab = 21 × 5 = 105 feet
Cost of 1 rubber tubing = $6.25 per yard
Convert 5 feet to yard:
1 yard = 3 feet
x yard = 5 feet
x = (5 × 1)/3
x = 5/3 feet.
So, the cost of 1 rubber tubing = $6.25 per 5/3
Cost of total length of tubbing needed = (105 × 6.25)/5/3 = (105 × 6.25) × 3/5
Cost of total length of tubbing needed = $393.75
Therefore, the cost to equip all the stations in the chemistry lab is calculated as: $393.75.
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Answer:
(a)96.77%
(b)3.23%
Step-by-step explanation:
Starting with the Michaelis-Menten equation which is used to model biochemical reactions:
Dividing both sides by 
![\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%7D%7BV_%7Bmax%7D%7D%3D%5Cdfrac%7B%5BS%5D%7D%7BK_M%20%2B%20%5BS%5D%7D)
Where:
maximum rate achieved by the system
=The Michaelis constant
Substrate concentration
(a) When ![[S]=30K_M](https://tex.z-dn.net/?f=%5BS%5D%3D30K_M)
![\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}\\\dfrac{v}{V_{max}}=\dfrac{30K_M}{K_M + 30K_M}\\\dfrac{v}{V_{max}}=\dfrac{30}{1 + 30}\\\dfrac{v}{V_{max}}=\dfrac{30}{31}\\$Expressed as a percentage\\\dfrac{v}{V_{max}}=\dfrac{30}{31}X100=96.77\%](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%7D%7BV_%7Bmax%7D%7D%3D%5Cdfrac%7B%5BS%5D%7D%7BK_M%20%2B%20%5BS%5D%7D%5C%5C%5Cdfrac%7Bv%7D%7BV_%7Bmax%7D%7D%3D%5Cdfrac%7B30K_M%7D%7BK_M%20%2B%2030K_M%7D%5C%5C%5Cdfrac%7Bv%7D%7BV_%7Bmax%7D%7D%3D%5Cdfrac%7B30%7D%7B1%20%2B%2030%7D%5C%5C%5Cdfrac%7Bv%7D%7BV_%7Bmax%7D%7D%3D%5Cdfrac%7B30%7D%7B31%7D%5C%5C%24Expressed%20as%20a%20percentage%5C%5C%5Cdfrac%7Bv%7D%7BV_%7Bmax%7D%7D%3D%5Cdfrac%7B30%7D%7B31%7DX100%3D96.77%5C%25)
(b)When ![K_M=30[S]](https://tex.z-dn.net/?f=K_M%3D30%5BS%5D)
![\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}\\\dfrac{v}{V_{max}}=\dfrac{[S]}{30[S] + [S]}\\\\=\dfrac{1[S]}{30[S] + 1[S]}\\=\dfrac{1}{30 + 1}\\\dfrac{v}{V_{max}}=\dfrac{1}{31}\\$Expressed as a percentage\\\dfrac{v}{V_{max}}=\dfrac{1}{31}X100=3.23\%](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%7D%7BV_%7Bmax%7D%7D%3D%5Cdfrac%7B%5BS%5D%7D%7BK_M%20%2B%20%5BS%5D%7D%5C%5C%5Cdfrac%7Bv%7D%7BV_%7Bmax%7D%7D%3D%5Cdfrac%7B%5BS%5D%7D%7B30%5BS%5D%20%2B%20%5BS%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%5BS%5D%7D%7B30%5BS%5D%20%2B%201%5BS%5D%7D%5C%5C%3D%5Cdfrac%7B1%7D%7B30%20%2B%201%7D%5C%5C%5Cdfrac%7Bv%7D%7BV_%7Bmax%7D%7D%3D%5Cdfrac%7B1%7D%7B31%7D%5C%5C%24Expressed%20as%20a%20percentage%5C%5C%5Cdfrac%7Bv%7D%7BV_%7Bmax%7D%7D%3D%5Cdfrac%7B1%7D%7B31%7DX100%3D3.23%5C%25)
The volume of a prism is area of the base times height.
This is a triangular prism. The base is a triangle.
The volume is area of the base times height, and the base is a triangle.
Find the area of the triangle and multiply by the height of the prism.
V = volume of the prism
A = area of the base
H = height of the prism
h = height of the triangle
b = base of the triangle
V = AH
V = (1/2)bhH
V = (1/2) * 9 ft * 7 ft * 15 ft
V = 472.5 ft^3
the math behind it:
your equation looks like this: .25x = 10
then you divide both sides by .25 and then ur equation looks like this: x=40
by the way the variable x stands for the number you are looking for. and since x=40, the number you are looking for is 40
well i hope i helped!