Answer:
Height of shuttle at that instant = 1.17 miles
Step-by-step explanation:
Refer the given figure.
C is the position of rocket and B is the position of observer.
Here we need to find AC, that is the height of shuttle at that instant.
Using trigonometric rules on ΔABC, we have
Height of shuttle at that instant = AC = 1.17 miles
An equvilent equation
remember you can do anything to an equation as long asyou do it to both sides
assuming yo have
x+y=1 and
x-3y=9
mulitply both by 2
2x+2y=2
2x-6y=18
those are equvilent
ok, solve initial
x+y=1
x-3y=9
multiply first equation by -1 and add to 2nd equation
-x-y=-1
<u>x-3y=9 +</u>
0x-4y=8
-4y=8
divide both sides by -4
y=-2
sub back
x+y=1
x-2=1
add 2
x=3
x=3
y=-2
(3,-2)
if we test it in other one
2x+2y=2
2(3)+2(-2)=2
6-4=2
2=2
yep
2x-6y=18
2(3)-6(-2)=18
6+12=18
18=18
yep
solution is (3,-2)
Study..................................................
Answer:
yes I think that's right because 14-12=26 so if you subtract 26 from 8 which that will give you 18
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Define x :
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Let the width be x.
Width = x
Length = 2x + 5 // Length is 5ft longer than twice the width
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Formula for Perimeter :
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Perimeter = 2 (Length + Width)
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Find Width :
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58 = 2 ( 2x + 5 + x) // Substitute Length and Width into formula
58 = 2 (3x + 5) // Combine like terms
58 = 6x + 10 // Apply distributive property
48 = 6x // Take away 10 from both sides
6x = 48 // Switch sides. Make x the subject
x = 8 // Divide by 6 on both sides
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Find Length and Width :
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Width = x = 8 ft
Length = 2x + 5 = 2(8) + 5 = 21 ft
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Answer: The length is 21 ft and the width is 8 ft.
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