The area of the garden enclosed by the fencing is
A(x, y) = xy
and is constrained by its perimeter,
P = x + 2y = 200
Solve for x in the constraint equation:
x = 200 - 2y
Substitute this into the area function to get a function of one variable:
A(200 - 2y, y) = A(y) = 200y - 2y²
Differentiate A with respect to y :
dA/dy = 200 - 4y
Find the critical points of A :
200 - 4y = 0 ⇒ 4y = 200 ⇒ y = 50
Compute the second derivative of A:
d²A/dy² = -4 < 0
Since the second derivative is always negative, the critical point is a local maximum.
If y = 50, then x = 200 - 2•50 = 100. So the farmer can maximize the garden area by building a (100 ft) × (50 ft) fence.
Answer:
120 ft squared
Step-by-step explanation:
First you find the areas of all the triangle surfaces and add them up
1/2 * b * h = 21
21 *4 = 84
Find the area of the square base and add the 2 values up
6^2 = 36
36+84 = 120
For this case we have:
By trigonometric property we have:
Where:
Substituting:
Clearing x we have:
Thus, the equation is:
Answer:
Answer: x=6 y=6
Step-by-step explanation:
Since the right parts of the equation are equal, therefore the left parts of the equation are also equal:
Divide both parts of the equation by 2:
Answer:
The point in which the graph crosses the x-axis is called the x-intercept and the point in which the graph crosses the y-axis is called the y-intercept.
Step-by-step explanation:
The x-intercept is found by finding the value of x when y = 0, (x, 0), and the y-intercept is found by finding the value of y when x = 0, (0, y).
