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In a circle with a 12-inch radius, find the length of a segment joining the midpoint of a 20-inch chord and the center of the circle.
x =
In a circle with a 12-inch radius, find the length of a segment joining the midpoint of a 20-inch chord and the center of the circle.
x =
2 answers:
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The length of the brace required is 4.3m
What is sine rule?
In a ΔABC a, b and c are the sides and A, B and C are angles then,
We can find the length, l as shown below:
Let AB=3m, BC=2m and AC=l
Let ∠A=25°
So, in ΔABC
∠C=39.34°
∠A+∠B+∠C=180°
∠B=180°-25°-39.34°
∠B=115.66°
l=4.2659
Rounding to nearest tenth of meter.
l=4.3m
Hence, the length of the brace required is 4.3m
Learn more about Sine Rule here:
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Answer:
the system of equation has infinite solution
Step-by-step explanation:
,
Solve the first equation for x_2
Subtract 5x1 on both sides
Now substitute -5x1 on second equation
0=0
So the system of equation has infinite solution