Answer:
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Step-by-step explanation:
Given;
The height function S(t) of the rocket as;
S(t) = -16t2 + 208t
The maximum altitude Smax, will occur at dS/dt = 0
differentiating S(t);
dS/dt = -32t + 208 = 0
-32t +208 = 0
32t = 208
t = 208/32
t = 6.5 seconds.
The maximum altitude Smax is;
Substituting t = 6.5 s
Smax = -16(6.5)^2 + 208(6.5)
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Answer:
it has infinitely many solutions because it can be solved by many technics
Step-by-step explanation:
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The length is 19.5 feet. this is because when you add the yards, it equals 15 feet. Next, add 1 + 2 feet from the first and second jump. 10+8 inches equal 1.5 feet. Next, add 15 feet+3 feet+1.5 feet to get 19.5 feet.
Answer:
I think its 6 :)
Step-by-step explanation: