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katen-ka-za [31]
4 years ago
13

A household product with an LD50 of 6 mg/kg of body weight would be expected to cause less harm to the skin and eyes than a prod

uct with an LD50 of 600mg/kg.
True
False
Medicine
2 answers:
erica [24]4 years ago
8 0

Answer:

True.

Explanation:

LD50 stands for Lethal Dose (50%). This is a toxicological parameter for determining whether or not a substance is toxic to a particular species after a few days of application and the amount of product applied has decreased by 50% of the amount applied. That is, LD50 refers to the toxicity content of the product at 50% of its quantity.

In this case, we can say that a household product with an LD50 of 6 mg/kg body weight causes less skin and eye damage than a product with an LD50 of 600 mg/kg. Because with 50% of the amount of these products, the product with LD50 of 6 mg/kg has a much smaller amount than the LD50 of 600 mg/kg.

baherus [9]4 years ago
7 0

Answer:

false

Explanation:

LD50 means median lethal dose.

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The acidic urinary pH increases the formation of uric acid or cysteine crystals. Therefore, kidney stones are very much influenced by urinary pH. More acidic urine and a higher frequency of uric acid stones have been associated with patients with inadequate ammonium excretion of metabolic syndrome.

Kidney stone disease results from deficiencies in urinary acidification, which result in the excretion of improperly alkaline or acidic urines, respectively. Patients with uncommon mendelian kidney stone variants have mutations in several enzymes, transporters, receptors, or channels. Numerous of these alterations either result in an increase in the excretion of chemicals that can crystallise or stone, a change in the composition of the urine that promotes crystal formation, or both.

Kidney stones can occur as a result of a variety of variables

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2. Ms Penny is a 69-year-old female with congestive heart failure. Her activity level and her energy
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Which Is REQUIRED for both ANAEROBIC respiration and AEROBIC RESPIRATION? (STUDY EXPOSED!)

By Patrick Campbell, real interesting video on the HIGH BLOOD PRESSURE.

Discover the video of this study : https://youtu.be/tc_GRuOp-w0

Explanation:

Patrick Campbell explained this study and what is the best practise.

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Tess has been admitted to the labor room in active labor at 40 weeks’ gestation. She is complaining of very painful contractions
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Tess needs to have a C-section right away!!!! The baby is probably breached that is why she is having pain. Have her husband hold her hand and tell her to breathe and it is okay.

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3 years ago
It is generally agreed that consumption of caffeine is not good for prenatal development. If Mary wants to avoid caffeine, which
MArishka [77]

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3 0
3 years ago
Question 11 a and b.
ladessa [460]

Answer:

a) 5040ways

b) 576ways

Explanation:

11a) There are 3 different bundles of reading materials each comprising of 4 comic and 3 magazines. The magazines and comics are placed together to form a bundle.

We are to determine the number of ways we can arrange these items in each of the bundle if there are no restrictions.

When there are no restrictions in combining items together, we can place the items in any positions.

Number of comics in one bundle = 4

Number of magazines in one bundle = 3

Total number of books = 4+3 = 7

For 7 reading materials in each bundle, there are 7 places we could pick for the first reading material, 6 for the next reading material, followed by 5, etc. Therefore, we have 7! total ways of arrangement.

7! = 7×6×5×4×3×2×1 = 5040ways

The number of ways we can arrange the items in one bundle if there are no restrictions on individual items to be placed = 5040ways

11b) We are to determine the number of permutations if the order of comic books in each bundle does not change.

For the order of comic books in each bundle not to change and they are arranged in one pile, it means all the comics are placed together.

The number of ways we can arrange 4 comic books placed together = 4!

4! = 4×3×2×1 = 24ways

Let the 4comics represent one entity = 1

The remaining reading materials = 7-4 = 3

The total number of reading material for the 1 entity and the remaining 3 = 3+1 = 4

The number of ways we can arrange these 1 entity and the remaining 3 books = 4!

4! = 4×3×2×1 = 24ways

The number of permutations if the order of comic books in each bundle does not change = 24×24 = 576ways

8 0
3 years ago
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