1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
barxatty [35]
3 years ago
7

Write this ratio As a fraction in lowest terms 30minutes to 50 minutes

Mathematics
1 answer:
omeli [17]3 years ago
5 0

Answer:

3:5

Step-by-step explanation:

Divide each side by 10 to simplify.

You might be interested in
Simplify square root of -13
tino4ka555 [31]

Answer:

\sqrt{13i}

Step-by-step explanation:

Theoretically, there is not square root of neither 13 nor a negative number so the special symbol is used to represent the square root of a number.

8 0
2 years ago
Could someone help me out with this problem I'm not that great at math​
VashaNatasha [74]

Answer:

Obtuse.

Step-by-step explanation:

4 0
3 years ago
For each set of probabilities, determine whether the events A and B are independent or dependent.
lozanna [386]

Answers:

  • (a) Independent
  • (b) Dependent
  • (c) Dependent
  • (d) Independent

========================================================

Explanation:

If events A and B are independent, then the two following equations must both be true

  • P(A | B) = P(A)
  • P(B | A) = P(B)

This is because the conditional probability P(A|B) means "P(A) when B has happened". If B were to happen, then P(A) must be the same as before. In other words, event B does not affect A, and vice versa.

For part (a), we have P(B) = 1/4 and P(B|A) = 1/4 showing that P(B|A) = P(B) is true, and therefore we can say the events are independent. We don't need the info that P(A) = 1/8.

------------------------

Unlike part (a), part (b) has the answer "dependent" because P(A) = 1/8 and P(A | B) = 1/3 differ in value. Event A starts off at probability 1/8, but then event B occurring means P(A) gets increased to 1/3. The prior knowledge about B changes the chances of A. The P(B) = 1/5 is unneeded.

------------------------

If A and B were independent, then,

P(A and B) = P(A)*P(B)

However,

P(A)*P(B) = (1/4)*(1/5) = 1/20

which is not the same as P(A and B) = 1/6. Therefore the two events are dependent.

------------------------

Refer back to part (a)

P(A) = 1/4 and P(A|B) = 1/4 are identical in value, so P(A|B) = P(A) which leads to the events being independent. Whether we know event B happened or not, it does not affect the outcome of event A. P(B) = 1/9 is unneeded.

7 0
2 years ago
If m angle N = (5x)° and m angle L = (x + 20)°, what is the value of x?
monitta
We can't tell. We need to know how the angles N and L are related.
6 0
3 years ago
Read 2 more answers
Use the diagram to solve for x.
Andreyy89
0 this is what I got
3 0
3 years ago
Other questions:
  • Rick deposits $1,000 into an investment account which earns 4% annually. Sally loans $1,000 to a friend, and the friend agrees t
    5·2 answers
  • A square garden has sides that each measure x+4 units. The garden's perimeter is 112 units. What is the value of x?
    11·2 answers
  • The population of a city is 50,000. It is increasing at an annual rate of 3%. What is the
    11·2 answers
  • Jack mixes yellow and blue paint to make green paint that he will use to paint his basement. He uses a ratio of 3 pints of yello
    10·1 answer
  • The domain of the following relation R {(3, −2), (1, 2), (−1, −4), (−1, 2)} is (1 point)
    9·1 answer
  • Jason flips a coin 100 times and lands on heads 59 times. He states that the theoretical probability of flipping a coin and gett
    13·1 answer
  • X + 2y = 6<br> (3x + 8y = 4
    13·1 answer
  • If f(x) =2x - 3, find the following<br><br> 1. f(-2)<br> 2. f(7)<br> 3. f(-4)
    9·1 answer
  • point k is between j and l. if jk = x^2 - 4x , kl = 3x - 2 and jl = 28 write and solve an equation to find the lengths of jk and
    10·1 answer
  • In the given figure, find the values of x and y.​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!