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dusya [7]
3 years ago
11

Math question help pls

Mathematics
1 answer:
tatyana61 [14]3 years ago
6 0
The second one is right
You might be interested in
Sam used 6 loaves of elf bread on a 8 day hiking trip. He wants to know how many loaves of elf bread he should pack for a 12 day
KonstantinChe [14]
If he eats 6 loaves in 8 days, that means he ate 0.75 of a loaf each day. (6 divided by 8 = 0.75)
In a 12 day trip,
# divided by 12 = 0.75;
so to undo division, you multiply.
12 x 0.75 = #
# = 9. So 9 loaves for 12 days.
5 0
3 years ago
???????????????????????????????????????????????????????????????????????????????
garik1379 [7]

Answer:

Step-by-step explanation:

This problem is just really long- it's trying to confuse you with complicated wording. Here's it demystified:

a)

t = 0 degrees Celsius

d = 1500 meters

Find the temperature, T.

b)

d = 300 meters

T = 26 degrees Celsius

Find the ground temperature, t.

NOTE: The temperatures are different! T is the final temperature and t is the ground temperature.

3 0
3 years ago
HELLOOOO HELP PLEASE
MA_775_DIABLO [31]

Answer:

2*log(x)+log(y)

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

   log_ba^c=c*log_ba

   So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: log_ba=x\implies b^x=a

   Now if we raise both sides to the power of c, we get the following equation: (b^x)^c=a^c

   Using the exponential identity: (x^a)^c=x^{a*c}

    We get the equation: b^{xc}=a^c

    If we convert this back into logarithmic form we get: log_ba^c=x*c

    Since x was the basic logarithm we started with, we substitute it back in, to get the equation: log_ba^c=c*log_ba

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

    log_b{ac}=log_ba+log_bc

    Now for a quick proof, let's just say: x=log_ba\text{ and }y=log_bc

    Now rewriting them both in exponential form, we get the equations:

    b^x=a\\b^y=c

    We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

    b^x*b^y=a*c

   Using the exponential identity: x^{a}*x^b=x^{a+b}, we can rewrite the equation as:

 

   b^{x+y}=ac

   taking the logarithm of both sides, we get:

   log_bac=x+y

   Since x and y are just the logarithms we started with, we can substitute them back in to get: log_bac=log_ba+log_bc

Now let's use these identities to rewrite the equation you gave

log(x^2y)

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

log(x^2)+log(y)

Now using the logarithm of a power to rewrite the log(x^2) we get:

2*log(x)+log(y)

3 0
2 years ago
G(x)=3x-4 find (gog) (x)
Anestetic [448]

Answer:

gog(x)=9x-16

Step-by-step explanation:

We are given g(x)=3x-4 and are asked to find (gog) (x)

gog(x)=g(g(x))

g(x)=3x-4

Hence

g(g(x))=g(3x-4)

=3(3x-4)-4

=9x-12-4

=9x-16

Hence

gog(x)=9x-16

5 0
3 years ago
Sophia wants to take out a loan of $6,000 with interest that compounds monthly. Use the formula A = P(1 + rn)n∗t to find which o
Naddika [18.5K]

Answer:

d

Step-by-step explanation:

FV = P (1 + r/m)^mn

FV = Future value  

P = Present value  

R = interest rate  

N = number of years

m = number of compounding

a. 6000x (1 + 0.04/12)^24 = 6498.86

b. . 6000x (1 + 0.03/12)^36 =6564.31

c. . 6000x (1 + 0.01/12)^48 = 6244.76

d. . 6000x (1 + 0.05/12)^60 =6630.47

4 0
3 years ago
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