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dusya [7]
3 years ago
11

Math question help pls

Mathematics
1 answer:
tatyana61 [14]3 years ago
6 0
The second one is right
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I need help please and thank you
Lesechka [4]

Answer:

Answer is 6 ft.

Step-by-step explanation:

4 0
3 years ago
How do I solve a 90° rotation about the origin
Dima020 [189]
Here is a way my class does this. We basically copy the graph and points on some tracing paper (you can find this in the art shop if you have time) and rotate the tracing paper 90* counter or 90* clockwise and there is your answer :)
4 0
3 years ago
What is the value of (3 + 2)2 - 5 * 3 +23?
tamaranim1 [39]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
Place (dlick and drag) one option from each of the lists below Into Its corresponding box to
earnstyle [38]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{3}}x+5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-1}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-1}\implies 3}}

so we're really looking for the equation of a line whose slope is 3 and passes through (1 , 10)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{10})\qquad \qquad \stackrel{slope}{m}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{3}(x-\stackrel{x_1}{1}) \\\\\\ y-10=3x-3\implies y=3x+7

5 0
2 years ago
Express M in terms of B and n: B = 3Mn 2
Molodets [167]

We are given the expression B=3Mn/2 and told to express M in terms of B and n. This means that we should apply mathematical operations on both sides of the equation so we "isolate " M on one side of the equality sign. We begin with the given equation

B=\frac{3\cdot M\cdot n}{2}

First, we multiply both sides by 2, so we get

2\cdot B=3\cdot M\cdot n

Next, we divide by 3 on both sides, so we get

\frac{2\cdot B}{3}=M\cdot n

Finally, we divide both sides by n, so we get

\frac{2\cdot B}{3\cdot n}=M

In this case, we have succesfully expressed M in terms of B and n

5 0
1 year ago
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