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3 years ago

Eva notices that she is taught by 3 male teachers and 4 female.

Mathematics

1 answer:

Phoenix [80]3 years ago

5 0

Answer:

male 3:4 female

52 females. 52/4 = 13

13 X 3 = 39

male 39 female 52

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Find the equation of the line that is perpendicular to y=1/3x-3 and passes through the point (3,-2)

sveta [45]

Answer:

y = -3x + 7

Step-by-step explanation:

Using the equation of line

y = mx + C

y - y_1 = m(x - x_1)

First find the slope

With eqn y = 1/3x - 3

Note, if two lines are perpendicular, their slope will be negative reciprocal

slope = m = -3/1

Using y - y_1 = m(x - x_1)

With point ( 3, -2)

x_1 = 3

y_1 = -2

y - (-2) = -3/1(x - 3)

y + 2 = -3/1(x -3)

Open bracket

y + 2 = -3(x - 3)/1

y + 2 = (-3x +9)/1

y = (-3x + 9 )/1 - 2

LCM is 1

y = -3x + 9 - 2

y = -3x + 7

The equation of the line is

y = -3x + 7

5 0

3 years ago

You randomly choose a marble from a bag containing 2 purple, 5 pink, and 2 Blue.

scoundrel [369]

Answer:

You have 5/9 chances of getting a pink marble

Step-by-step explanation:

There are 5 pink marbles and 9 in all which gives you the fraction 5 out of 9

3 0

3 years ago

Here’s the question

kirill115 [55]

Answer:

D. Red

Step-by-step explanation:

Green, 5/8 times two is 10/8 = 1 2/8 = 1 1/4

7 0

4 years ago

Read 2 more answers

Pls help me

spayn [35]

Step-by-step explanation:

2x + x + 57 = 90

3x = 33

x = 11

m1 = 2 × 11 = 22°

m2 = 11 + 57 = 68°

check: 22 + 68 = 90

3 0

3 years ago

MATH HELP PLZ!!!

RoseWind [281]

Answer:

a) $tan (157.5) = \frac{1-cos 315}{sin315}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

cos 330° = 1- 2 sin² (165°)

Step-by-step explanation:

Step(i):-

By using trigonometry formulas

cos2∝ = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ = 2 cos² ∝/2

$cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}$

cos2∝ = 1- 2 sin² ∝

cos∝ = 1- 2 sin² ∝/2

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

Step(i):-

Given

$tan\alpha = \frac{sin\alpha }{cos\alpha }$

we know that trigonometry formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

Given

$tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }$

put ∝ = 315

$tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }$

multiply with ' 2 sin (∝/2) both numerator and denominator

$tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2} }{2sin(\frac{315}{2} cos(\frac{315}{2}) }$

Apply formulas

$sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )$

1- cos∝ = 2 sin² ∝/2

now we get

$tan (157.5) = \frac{1-cos 315}{sin315}$

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 330° above formula

$sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}$

$sin^{2} (165) = \frac{1-cos (330) }{2}$

$sin (165) =\sqrt{ \frac{1-cos (330) }{2}}$

c )

$sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}$

put ∝ = 315° above formula

$sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}$

$sin^{2} (157.5) = \frac{1-cos (315) }{2}$

cos∝ = 1- 2 sin² ∝/2

put ∝ = 330°

$cos 330 = 1 - 2sin^{2} (\frac{330}{2} )$

cos 330° = 1- 2 sin² (165°)

3 0

3 years ago