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Simora [160]
3 years ago
5

Determine algebraically whether the function is even, odd, or neither even nor odd.

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0
For a function (fn) to be odd:
f(x) = - f(-x)
For a fn to be even:
f(x) = f(-x)
For a fn to be neither even nor odd
f(x) != f(-x)  [No Relation]

(-x)^n = x^n   for n -> even
(-x)^n = -x^n  for n -> odd
In your example:

f(x) = -4x^3 + 4x
f(-x) = -4 (-x)^3 + 4 (-x)^1  ( 3 and 1 are odd powers )
f(-x) = 4x^3 - 4x   (take -1 common to do the check)
f(-x) = -( -4x^3 + 4x ) = - f(x)  [between the bracket was the original fn]

f(x) = - f(-x)   
so the function is odd also called symmetric about the origin
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PLEASE ANSWER WITH THE RIGHT ANSWER THANKS
Anon25 [30]
<span>9.23076923076923%

i think by rounding it it would be 9.23%</span>
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