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3 years ago

If ABC~DEF what is the length of BC? If ABC~DEF what is the length of EF?

Mathematics

1 answer:

marysya [2.9K]3 years ago

3 0

BC would equal the same as EF, they are similar. All you would have to do is figure out the pre image (BC) of EF.

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The sequence 2, 3, 5, 6, 7, 10, … consists of

Kay [80]

The 76th term is 86.

<h3>What is sequence?</h3>

A sequence is an enumerated collection of objects in which repetitions are allowed and order matters. Like a set, it contains members (also called elements, or terms). The number of elements (possibly infinite) is called the length of the sequence.

Given:

2, 3, 5, 6, 7, 10, …

The sequence consists of all natural numbers which are neither perfect squares nor perfect cubes.

We can as well sum the number of squares and cubes in the range with the number of the required term i.e

Number of squares = 8 ( 4,9,16,25,36,49,64,81)

Number of cubes = 2 (8 and 27; excluding 64 which is as well a square)

Required term = 75

So, 8+2+75 = 85.

Hence, the 85th term counting from 2 ( i.e 86) is the 75th term.

Learn more about sequence here:

brainly.com/question/16614966

#SPJ1

3 0

2 years ago

A school principal plans to form teams from 126 third-graders, 180 fourth-graders, and 198 fifth-graders so that there is the sa

marissa [1.9K]

Answer:

There are 9 teams possible each having 14 third-graders, 20 Fourth-graders, 22 Fifth-graders

Step-by-step explanation:

126 third-graders

180 fourth-graders

198 fifth-graders

Find the highest common factor of 126, 180, 198

Factors of 126: 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126.

Factors of 180 : 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180

Factors of 198: 1, 2, 3, 6, 9, 11, 18, 22, 33, 66, 99, 198.

The highest common factor of 126, 180, 198 is 9

The largest possible number of teams that can be formed is 9

Each team has

third-graders = 126 / 9

= 14

Fourth-graders = 180 / 9

= 20

Fifth-graders = 198 divided by 9

= 22

There are 9 teams possible each having 14 third-graders, 20 Fourth-graders, 22 Fifth-graders

3 0

3 years ago

PLEASE HELP FAST!!!!

maks197457 [2]

Answer:

Step-by-step explanation:

use desmos.com

6 0

2 years ago

According to science, Earth is about 4.5 billion years old and written human history extends back about 10,000 years. Suppose yo

zalisa [80]

It begins in 30000 bc

5 0

3 years ago

Read 2 more answers

Quadrilateral ABCD is inscribed in a circle with angle measures m∠A = (11x − 8)°, m∠B = (3x2 + 1)°, m∠C = (15x + 32)°, and m∠D =

dimulka [17.4K]

Answer:

No for all of the 4 values

Step-by-step explanation:

The sum of the internal angles of a quadrilateral is always 360°, so we have that:

m∠A + m∠B + m∠C + m∠D = 360

11x - 8 + 3x2 + 1 + 15x + 32 + 2x2 - 1 = 360

5x2 + 26x - 320 = 0

Solving the quadratic function using Bhaskara's formula, we have:

Delta = 26^2 + 4*5*320 = 7076

sqrt(Delta) = 84.12

x1 = (-26 + 84.12)/10 = 5.81

x2 = (-26 - 84.12)/10 = -11.01 (this value will generate negative angles, so it is not valid).

Now, finding the angles, we have:

m∠A = 11*5.81 - 8 = 55.91°

m∠B = 3*(5.81)^2 + 1 = 102.27°

m∠C = 15*5.81 + 32 = 119.15°

m∠D = 2*(5.81)^2 - 1 = 66.51°

As all these values are different from the values shown, the answer is No for all of them.

8 0

3 years ago