I believe the balanced chemical equation is:
C6H12O6 (aq) + 6O2(g)
------> 6CO2(g) + 6H2O(l)
First calculate the
moles of CO2 produced:
moles CO2 = 25.5 g
C6H12O6 * (1 mol C6H12O6 / 180.15 g) * (6 mol CO2 / 1 mol C6H12O6)
moles CO2 = 0.8493 mol
Using PV = nRT from
the ideal gas law:
<span>V = nRT / P</span>
V = 0.8493 mol *
0.08205746 L atm / mol K * (37 + 273.15 K) / 0.970 atm
<span>V = 22.28 L</span>
A hydrocarbon has only hydrogen and carbon in it. the 1st, 3rd and 4th option all include Oxygen so the only hydrocarbon is option 2
Answer:
Explanation:
N = Final mass of atom = 125 g
= Initial mass of atom = 16000 g
t = Time taken = 163.24 days
= Half life
We have the relation
The half life of the atom is .
