Answer:
The answer to your question is: 70.7 %
Explanation:
Equation
Xe + 2F₂ ⇒ XeF₄
limiting reactant = Xe
Xe is the limiting reactant because the ratio is:
theoretical = 131/ 76 = 1.72 g
experimental ratio = 130/100 = 1.3 the amount of F increased.
131.3 g of Xe ------------------ 207 g of XeF₄
130 g of Xe ------------------- x
x = (130 x 207) / 131.3
x = 205 g of XeF₄
% yield = 145 / 205 x 100
% yield = 70.7
Answer is: electronegativity.
Electronegativity (χ) is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.
Atoms with higher electronegativity attracts more electrons towards it, electrons are closer to that atom.
For example, in ionic salt lithium fluoride (LiF), fluorine has electronegativity approximately χ = 4 and lithium χ = 1 (Δχ = 4 - 1; Δχ = 3), fluorine attracts electron and it has negative charge and lithium has positive charge.
Lithium and fluorine are in period 2, lithium is metal far left and fluorine is nonmetal far in the right at the period. Nonmetals have higher tendency to attract shared electrons.
I think g (sorry if it’s wrong)
Answer:
Explanation:
For the pH value of a buffer solution , the Henderson formula given is as follows
pH = pKa + log [ A⁻] / [AH ]
Now let us discuss about the phosphoric and succinic acid . The phosphoric acid has a pKa value of 2.3 and for succinic acid , the pKa value is 4.2 . The pKa value of succinic acid is more close to 5 . So to achieve pH value of 5 , succinic acid is a better alternative . The value of [ A⁻] / [AH ] is kept almost equal to 1 to increase the buffer capacity .