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algol [13]
3 years ago
10

_________ energy is to the fission and fusion within an atom as ________ energy is to the fission of atomic compounds.

Chemistry
2 answers:
xeze [42]3 years ago
7 0
I would say C bc I don’t rlly think it’s A or B
Troyanec [42]3 years ago
6 0

Answer:

Watch Naruto that's the answer

Explanation:

You might be interested in
A 0.271g sample of an unknown vapor occupies 294ml at 140C and 874mmHg. The emperical formula of the compound is CH2. How many m
Phoenix [80]
Using PV = nRT, we can calculate the moles of the sample.
874 mmHg = 116,524 Pa
n = PV/RT
n = 116,524 x 294 x 10⁻⁶ / 8.314 x (140 + 273)
n = 9.98 x 10⁻³ mol

moles = mass / Mr
Mr = 0.271/9.98 x 10⁻³
Mr = 27.2
Mass of empirical formula = 14
Repeat units = 27.2 / 14 ≈ 2

Formula of substance:
C₂H₄

Combustion equation:
C₂H₄ + 3O₂ → 2CO₂ + 2H₂O

1 mole produces 2 moles of CO₂, so 3 moles will produce 6 moles CO₂
7 0
3 years ago
Why are relative atomic masses on the periodic tables not whole numbers?
Kobotan [32]

Answer:

They are averages.

Explanation:

atomic numbers on periodic tables are derived from the average value of all the isotopes of the element. So being averages they are sometimes not integers.

6 0
3 years ago
Read 2 more answers
In which 2 states of matter can a substance take the shape of its container?
Natasha2012 [34]

Answer:

solid and liquid

Explanation:

5 0
3 years ago
Read 2 more answers
Atomic mass number of first 30 elements
dangina [55]

Answer:

Element Atomic Number Atomic Mass

Nickel          27                          58.6934

Cobalt             28                   58.9332

Copper            29                  63.546

Zinc                   30                            65.39

Explanation:

4 0
3 years ago
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
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