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Nataly [62]
3 years ago
13

hii um i'm in middle school and i'm doing the body in science. alot of boys point at me since i am a thicker one (not fat though

lol just kind of curvy). how can i just ignore them w/o feeling embarrassed? :(

Chemistry
1 answer:
miss Akunina [59]3 years ago
8 0

Answer:

Just show them their place.

Explanation:

hope this helps

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An acidic fog in pasadena was found to have a ph of 2.50. which expression represents this ph measurement?
joja [24]

Supposing a temperature of 25 degrees and supposing that all activity coefficients are 1 

pH = -log[H+] 
pOH = -log[OH-] 
pH + pOH = 14 

Thus a pH of 2.50 would mean that the [H+], the concentration of the hydrogen ion, would be 10^(-2.50) 

pH + pOH = 14 
pOH = 14 - pH = 14 - 2.5 = 11.5 
MOH- levels would be coordinated with pOH 
pOH = -log[OH-] ==> [OH-] = [MOH-] = 10^-pOH = 10^-11.5 = 3.2 x 10^-12 

Therefore, MOH¯ = 3.2 × 10¯12 M 

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olganol [36]
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6 0
3 years ago
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Solutions and colloids which contain similarly sized particles can be effectively separated using paper filtration.
mojhsa [17]
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How much heat energy is required to melt 75g of ice at 0°C?
Mnenie [13.5K]

The enthalpy change for melting ice is called the entlaphy of fusion. Its value is 6.02 kj/mol. This means for every mole of ice we melt we must apply 6.02 kj of heat. We can calculate the heat needed with the following equation:

Q = N x ΔH

where:

Q  = heat

N  = moles  

ΔH  = enthalpy

In this problem we would like to calculate the heat needed to melt 35 grams of ice at 0 °C. This problem can be broken into three steps:


1. Calculate moles of water

2. multiply by the enthalpy of fusion

3. Convert kJ to J.


Step 1 : Calculate moles of water

[ 75g ] x (\frac{1 mol}{18.02g} ) =

Step 2 : Multiply by enthalpy of fusion

Q = N × ΔH  = <em> [ Step 1 Answer ]</em> ×  6.02 =

Step 3 : Convert kJ to J

[ Step 2 Answer ] x (\frac{1000j}{1kJ} ) =

Finally rounding to 2 sig figs (since 34°C has two sig figs) we get


Q Would Equal ____

4 0
3 years ago
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