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Vikentia [17]
3 years ago
10

A drinking water plant adds 500 grams of fluoride to a water tank containing 500,000 liters of drinking water. what is the conce

ntration of fluoride in the water in parts-per-million (ppm)?
Chemistry
1 answer:
nlexa [21]3 years ago
5 0
Answer is: <span>concentration of fluoride in the water in parts-per-million is 1 ppm.
</span>Parts-per-million (10⁻⁶) is<span> present at one-millionth of a </span>gram per gram of sample solution, f<span>or example mg/kg.
</span>m(fluoride) = 500 g · 1000 mg/g = 500000 mg.
m(water) = d(water) · V(water).
m(water) = 1 kg/L · 500000 L.
m(water) = 500000 kg.
arts-per-million = 500000 mg ÷ 500000 kg = 1 mg/kg = 1 ppm.
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Answer:

F centripetal force (tension) = 275.9  N

Explanation:

Given data:

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Solution:

F centripetal force (tension) =  m.v² / R

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F centripetal force (tension) = 1.50 kg . 95.65 m²/s² / 0.520 m

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387 mL x 1.11g/mL = 429.57 g
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