Answer:
32.1 g
Explanation:
Step 1: Write the balanced combustion reaction
C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O
Step 2: Calculate the moles corresponding to 97.4 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
97.4 g × 1 mol/44.01 g = 2.21 mol
Step 3: Calculate the moles of butane that produced 2.21 moles of carbon dioxide
The molar ratio of C₄H₁₀ to CO₂ is 1:4. The moles of C₄H₁₀ required are 1/4 × 2.21 mol = 0.553 mol
Step 4: Calculate the mass corresponding to 0.553 moles of C₄H₁₀
The molar mass of C₄H₁₀ is 58.12 g/mol.
0.553 mol × 58.12 g/mol = 32.1 g
Answer:
343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.
Explanation:
A typical carbon–carbon bond requires 348 kJ/mol=348000 J/mol
Energy required to breakl sigle C-C bond:E
where,
E = energy of photon
h = Planck's constant = 
c = speed of light = 
= wavelength of the radiation
Now put all the given values in the above formula, we get the energy of the photons.
343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.
Answer:
there is no image there so i do not know
Explanation:
The chemical formula : X₃Y₂
<h3>Further explanation </h3>
The noble gas element is a stable class of elements. The noble gas element is monatomic. Stability of noble gases is caused by an electron configuration that has a stable configuration of 8 (has 8 valence electrons) except He with a duplet configuration (has 2 valence electrons)
Other elements that do not yet have electron configurations such as noble gases will try to achieve their stability by forming bonds between elements.
This is generally called the octet rule
X has 2 valence electrons.to achieve stability, element X will release 2 electrons to form X²⁺
Y has 5 valence electrons, to achieve stability, the element Y will attract/ add electrons to form Y³⁻
The two compounds will form a compound with the charges crossed : X₃Y₂
Answer:
1.25 moles
Explanation:
First, we need to balance the equation. Essentially, this means making sure we have the same number of each atom on each side.
On the left side, we currently have:
- 1 Co atom
- 2 F aomts
On the right side, we have:
- 1 Co atom
- 3 F atoms
To balance it, add a 2 to Co on the left, 3 to F2 on the left, and 2 to CoF3 on the right:
→ 
Now, we have 1.25 moles of Co, and since the ratio between Co and CoF3 is 1:1, we also have 1.25 moles of CoF3.
Thus, the answer is 1.25 moles.
