All categories

3 years ago

What is the square root of 10,000

Mathematics

2 answers:

yaroslaw [1]3 years ago

8 0

Answer:

100

Step-by-step explanation:

The square root of 10000 can be written as (10000)1/2. Thus,

(10000)^/2 = (100 × 100)^1/2

(10000)^1/2 = [(100)2]^1/2

(10000)^1/2 = (100)^2/2

(10000)^1/2 = (100)^1

So,

√10000 = 100

Setler [38]3 years ago

7 0

100 and -100 are the two solutions for the square root of 10,000

You might be interested in

Help please! I'm the worst at math. :(

Artist 52 [7]

Points of intersection are (0,0),(0,8),(10,0),(4,6) plugging them into the equation you get 0,24,10,22. I don't know if you're looking for max value or min value.

3 0

3 years ago

This Bar Chart shows how many days it took for 12 corn seedlings to emerge.

AURORKA [14]

Answer:

There should be a picture of a bar chart, attach it so i can answer the question.

Step-by-step explanation:

PLease mark as brainliest lol

7 0

3 years ago

(03.02 HC) Stan, Liam, and Louise are competing in a cooking competition. They all used different amounts of flour from a can co

noname [10]

Answer:

Liam

Step-by-step explanation:

First we can change 12% to 0.12 then multiply 0.12 with 5 and get 0.6, so Stan has 0.6 of the flour, and we see that 0.11 is greater than 0.7 and 0.6

4 0

3 years ago

Read 2 more answers

Ball bearings are manufactured with a mean diameter of 5 millimeters(mm). Because of variability in the manufacturing process, t

dexar [7]

Answer:

a) 0.0668 of ball bearings have a diameter more than 5.03 mm

b) 0.0124 of ball bearings will be discarded

c) The plant manager should expect to discard 372 balls.

d) 57,710 ball bearings should be manufactured.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 5, \sigma = 0.02$

(a) What proportion of ball bearings has a diameter more than 5.03 mm?

This is 1 subtracted by the pvalue of Z when X = 5.03. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.03 - 5}{0.02}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 of ball bearings have a diameter more than 5.03 mm

(b) Any ball bearings that have a diameter less than 4.95 mm or greater than 5.05 mm are discarded. What proportion of ball bearings will be discarded?

Lower than 4.95 or greater than 5.05. Both these proportions are the same, so we find one of them, and multiply by 2.

Less than 4.95:

pvalue of Z when X = 4.95. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.95 - 5}{0.02}$

$Z = -2.5$

$Z = -2.5$ has a pvalue of 0.0062

2*0.0062 = 0.0124

0.0124 of ball bearings will be discarded.

(c) Using the results of part (b), if 30,000 ball bearings are manufactured in a day, how many should the plant manager expect to discard?

0.0124 of 30,000. So

0.0124*30000 = 372

The plant manager should expect to discard 372 balls.

(d) If an order comes in for 50,000 ball bearings, how many bearings should the plant manager manufacture if the order states that all ball bearings must be between 4.97 mm and 5.03 mm?

Proportion of bearings between 4.97 mm and 5.03 mm:

pvalue of Z when X = 5.03 subtracted by the pvalue of Z when X = 4.97. So

X = 5.03

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.03 - 5}{0.02}$

$Z = 1.5$

$Z = 1.5$ has a pvalue of 0.9332

X = 4.97

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4.97 - 5}{0.02}$