Answer:The claim is correct
Explanation:Assume the given triangle ABCperimeter of triangle ABC = AB + BC + CA ............> I
Now, we have:D is the midpoint of AB, this means that:
AD = DB = (1/2) AB ..........> 1E is the midpoint of AC, this means that:
AE = EC = (1/2) AC ...........> 2DE is the midsegment in triangle ABC, this means that:
DE = (1/2) BC ...........> 3perimeter of triangle ADE = AD + DE + EA
Substitute in this equation with the corresponding lengths in 1,2 and 3:perimeter of triangle ADE = (1/2) AB + (1/2) BC = (1/2) AC
perimeter of triangle ADE = (1/2)(AB+BC+AC) .........> IIFrom I and II, we can prove that:perimeter of triangle ADE = (1/2) perimeter of triangle ABC
Which means that:perimeter of midsegment triangle is half the perimeter of the original triangle.
Hope this helps :)
Answer:
there is no question for me to tell you what it is
9514 1404 393
Answer:
x = {7, 1, -4}
Step-by-step explanation:
Dividing the given factor from the polynomial using synthetic division, we get ...
f(x) = (x -7)(x^2 +3x -4)
Factoring the quadratic* gives ...
f(x) = (x -7)(x -1)(x +4)
The zeros are the values of x that make these factors be zero:
x = {7, 1, -4}
_____
* The constants in the binomial factors are factors of -4 that have a sum of +3. Those are (-1)(4) = -4. -1+4 = 3.
103 x 47 = 4841 - 8 = 4833
The awnser is 4,833