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2 years ago

Given ABC is similar to DEF and BC = 8, what is the value of EF?

Mathematics

1 answer:

lbvjy [14]2 years ago

6 0

In similar triangles ratios of corresponding sides are constant, so

|AB|/|DE| = |BC|/|EF|

5/10 = 8/|EF|

|EF| = (8*10)/5 = 16

|EF| = 16

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Multiply or divide as indicated. Y^-9•y^-8•y^10

BabaBlast [244]

Answer:

1 / y^7

Step-by-step explanation:

Y^-9•y^-8•y^10

= y^10 / y^9•y^8

= y^10 / y^17

= 1 / y^7

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3 years ago

Find the value of 7p – 3q when p= 8 and q = -5

EastWind [94]

Step-by-step explanation:

7p – 3q

if p= 8 and q = -5

7(8)-3(-5)

56+15

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2 years ago

Read 2 more answers

Simplly the square root of 75z^18

notsponge [240]

Answer:5√(3)z^9

Step-by-step explanation:

Square root of 75z^18

√(75z^18)

√(75) x √(z^18)

√(25x3) x (z^18)^(1/2)

√(25) x √(3) x z^(18x1/2)

5 x √(3) x z^9

5√(3)z^9

8 0

3 years ago

Money Flow The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the

77julia77 [94]

Answer:

Present value = $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5% compounded continuously

Now,

Accumulated Value of the money flow = $1000e^{0.05t}$

The present value of the money flow = $\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt$

= $1000\int\limits^4_0 {e^{0.015t}} \, dt$

= $1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4$

= $1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]$

= 1000 × [70.7891 - 66.6667]

= $4,122.4

Accumulated interest = $e^{rt}\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t}} \, dt$

= $e^{0.035\times4}\times4,122.4$

= $4,742

8 0

2 years ago

If the three angles of a quadrilateral are 120, 130, 100 then what is the fourth angle?

nalin [4]

Answer:

c. 40

Step-by-step explanation:

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2 years ago