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musickatia [10]
4 years ago
15

An investment of 75,000 increases at a rate 12.5% per year. Find the value of the investment after 30 years.

Mathematics
2 answers:
dexar [7]4 years ago
5 0
For this case we have an equation of the form:
 y = A * (b) ^ t
 Where,
 A: initial amount
 b: growth rate
 t: time
 Substituting values we have:
 y = 75000 * (1.125) ^ t
 For 30 years we have:
 y = 75000 * (1,125) ^ 30
 y = 2568247.871
 Rounding:
 y = 2568248
 Answer:
 
the value of the investment after 30 years is:
 
A. $ 2,568,248
enyata [817]4 years ago
4 0
Given that a<span>n investment of 75,000 increases at a rate 12.5% per year. Find the value of the investment after 30 years. 
Solution
The value after 30 years will be given by
A=P(1+r/100)^n
where:
P=principple
r=rate
n=time
from the information:
P=75000, r=12.5%, n=time
thus plugging the values we obtain:
A=75000(1+12.5/100)^30
A=75000(1.125)^30
A=2,568,247.871

Answer: </span><span>A. $2,568,248</span>
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Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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The population proportion have the following distribution

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Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can assume an estimated proportion of \hat p =0.5 since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Hope you have understood this....

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