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2 years ago

9

Pls help asap

2 answers:

Sergeu [11.5K]2 years ago

6 0

Answer:

Step-by-step explanation:

100,000 = $10^{5}$

$\frac{1}{100,000}$ = $10^{-5}$

100,000 × $\frac{1}{100,000}$ = $10^{5}$ × $10^{-5}$ = $10^{5+(-5)}$ = $10^{0}$ = 1

VMariaS [17]2 years ago

3 0

Answer: Addition

Step-by-step explanation: You can represent that as 10^5*10^-5

If you add the exponent values, you get 10^0 which is equal to 1. If you multiply them, you get 10^-25 which is wrong.

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Multiply 18/5 * 15/14

Katena32 [7]

18/5= 3.6 and 15/14=1.07

3.6*1.07= 3.852

3 0

3 years ago

If the expression $3^1 times 9^2 times 27^3 \times 81^4 is simplified to the form 3^n, what is the value of n?

Darina [25.2K]

Answer:

$n=30$

Step-by-step explanation:

Given expression:

$3^1\times 9^2\times 27^3\times 81^4$

The given expression needs to be simplified to the form $3^n$

Applying the exponents rule to simplify.

$3^1\times 9^2\times 27^3\times 81^4$

Writing all numbers as product of 3.

⇒ $3^1\times (3\times3)^2\times (3\times3\times3)^3\times (3\times3\times3\times3)^4$

Writing each in exponents form.

⇒ $3^1\times (3^2)^2\times (3^3)^3\times (3^4)^4$

Using power of a power rule $[\ (a^x)^y=a^{xy}\ ]$

⇒ $3^1\times 3^4\times 3^9\times 3^16$

Using multiplication rule of exponents $[\ a^x\times a^y=a^{x+y}\ ]$

⇒ $3^{1+4+9+16}$

⇒ $3^{30}$

So we have $3^n=3^{30}$

∴ $n=30$

8 0

2 years ago

Which expression is equivalent to

pickupchik [31]

Answer:

B. 2x-3

Step-by-step explanation:

14 and 21 have a common factor which is 7 so divide both by 7 to get 2x-3.

8 0

3 years ago

For f(x) = 4x+ 1 and g(x) = x2 - 5, find (f+ g)(x).

horrorfan [7]

Answer:

x^2+4x-4

Step-by-step explanation:

4x+1+x^2-5

x^2+4x-4

6 0

3 years ago

Read 2 more answers

Can someone do this fast ? I need it for tomorrow

gregori [183]

Answer:

Step-by-step explanation:

hg(x) means you multiply h(x) times g(x) and then we will set it equal to $3x^2+x-1$ .

hg(x) = $x^2(x+2)$ which simplifies to

$x^3+2x^2$ . Now set that equal to $3x^2+x-1$ :

$x^3+2x^2=3x^2+x-1$ and get everything on the same side and factor:

$x^3-x^2-x+1=0$ . Factor by grouping:

$(x^3-x^2)-(x+1)=0$ and factor out what's common in each set of ( ):

$x^2(x-1)-1(x-1)=0$ which factors out to

$(x^2-1)(x-1)=0$ . But $x^2-1$ factors somoe to:

(x + 1)(x - 1)(x - 1) = 0 So the solutions for this are

x = -1, 1

7 0

2 years ago