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dusya [7]
4 years ago
14

The graph of g(x) ​​is the graph of f(x)=5x+15 compressed horizontally by a factor of ​ 1/5 ​ .

Mathematics
2 answers:
Vlad [161]4 years ago
7 0
Consider the value of f at x=2.

f(2)=5*2+15=10+15=25. Thus, we have the point (2, 25) in the graph of f.

The graph of g is the graph of f compressed horizontally by a factor of 1/5. 

So at 2, the y-coordinate is 25(1/5=5). That is, we have the point (2, 5).


All pairs (x, y) in f can be described by (x, 5x+15), thus, all pairs (x, y) in g can be described by (x, (5x+15)/5), that is (x, x+3). Thus, the rule for g is :

g(x)=x+3.


Answer: <span>A) g(x)=x+3</span>
kompoz [17]4 years ago
4 0
The answer is actually g(x)=25x+15 just took the test btw are you in k12?
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Answer:

Step-by-step explanation:

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What is the equation of the following line written in general form (4,5) (1,2)
a_sh-v [17]
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because the slope is 1 shown by this table:
1,2
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and if the slope is one then 2-1 is 1 and the y intercept is 0,1.

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A store sold a case of scented candles for $17.85 that had been marked up 110%. What was the original price?
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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
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