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dusya [7]
3 years ago
14

The graph of g(x) ​​is the graph of f(x)=5x+15 compressed horizontally by a factor of ​ 1/5 ​ .

Mathematics
2 answers:
Vlad [161]3 years ago
7 0
Consider the value of f at x=2.

f(2)=5*2+15=10+15=25. Thus, we have the point (2, 25) in the graph of f.

The graph of g is the graph of f compressed horizontally by a factor of 1/5. 

So at 2, the y-coordinate is 25(1/5=5). That is, we have the point (2, 5).


All pairs (x, y) in f can be described by (x, 5x+15), thus, all pairs (x, y) in g can be described by (x, (5x+15)/5), that is (x, x+3). Thus, the rule for g is :

g(x)=x+3.


Answer: <span>A) g(x)=x+3</span>
kompoz [17]3 years ago
4 0
The answer is actually g(x)=25x+15 just took the test btw are you in k12?
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From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
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Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

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et grass cowbowcowbow

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