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2 years ago

The shape of a molecule with no multiple bonds and a central atom with two bonding pairs and too lone pairs of electrons is

Chemistry

1 answer:

My name is Ann [436]2 years ago

3 0

Explanation:

If there are two bond pairs and two lone pairs of electrons the molecular geometry is angular or bent (e.g. H2O). Five electron pairs give a starting point that is a trigonal bipyramidal structure.

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A 0.500-g sample of KCl is added to 50.0g of water in a calprimeter (Figure 5.12) If the temperature decreases by 1.05C. what is

Sauron [17]

Answer : The reaction is endothermic.

Explanation :

Formula used :

$Q=m\times c\times \Delta T$

where,

$\Delta T$ = change in temperature = $1.05^oC$

Q = heat involved in the dissolution of KCl = ?

m = mass = 0.500 + 50.0 = 50.5 g

c = specific heat of resulting solution = $4.18J/g^oC$

Now put all the given value in the above formula, we get:

$Q=50.5g\times 4.18J/g^oC\times 1.05^oC$

$Q=+221.64J$

The heat involved in the dissolution of KCl is positive that means as the change in temperature decreases then the reaction is endothermic and as the change in temperature increases then the reaction is exothermic.

Hence, the reaction is endothermic.

8 0

2 years ago

If an atom has 35 protons in nucleus how many neutrons will it have orbiting the nueclues

Dvinal [7]

Answer

Because the two particles have an equal charge, the charges will cancel out and give the atom an overall charge of 0. So, if at atom has 35 protons in the nucleus, we could expect it to have 35 electrons orbiting that nucleus.

Explanation:

8 0

2 years ago

Which of the following organisms would likely be found on a decaying deer carcass (dead deer)?

TEA [102]

Answer:

c. bacteria and fungus

Explanation:

3 0

2 years ago

Read 2 more answers

What is the Ka of a weak acid (HA) if the initial concentration of weak acid is 4.5 x 10-4 M and the pH is 6.87? (pick one)

rewona [7]

Answer:

Ka = $4.04 \times 10^{-11}$

Explanation:

Initial concentration of weak acid = $4.5 \times 10^{-4}\ M$

pH = 6.87

$pH = -log[H^+]$

$[H^+]=10^{-pH}$

$[H^+]=10^{-6.87}=1.35 \times 10^{-7}\ M$

HA dissociated as:

$HA \leftrightharpoons H^+ + A^{-}$

(0.00045 - x) x x

[HA] at equilibrium = (0.00045 - x) M

x = $1.35 \times 10^{-7}\ M$

$Ka = \frac{[H^+][A^{-}]}{[HA]}$

$Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 - 0.000000135}$

0.000000135 <<< 0.00045

$Therefore, Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 } = 4.04 \times 10^{-11}$

5 0

2 years ago

The pentose phosphate pathway (PPP) is localized to the cytosol.

DIA [1.3K]

Answer: The pentose phosphate pathway (PPP) is localized to the cytosol because fatty acid synthesis uses the NADPH generated by the PPP.

Explanation:

The pentose phosphate pathway is mainly catabolic and provides an alternative glucose oxidizing pathway for the generation of NADPH that is required for reductive biosynthetic reactions such as those of cholesterol biosynthesis, bile acid synthesis, steroid hormone biosynthesis, and fatty acid synthesis.

Fatty acid biosynthesis occurs in the cytosol and requires the reducing equivalent NADPH in large amounts. <em>The main source of generating NADPH in animal cells, the pentose phosphate pathway is therefore, localized in the cytosol in order to furnish a strongly reducing environment for fatty acid biosynthesis to proceed.</em>

5 0

2 years ago