<span>The atomic weight of 13C should be pretty close to 13.0. (If you have the exact mass, use it in the problem.) So,
9.00 g / 13.0 g/mol = 0.692 moles
Therefore, the answer should be 0.692 moles are in 9.00 g of 13C.</span>
Answer:
The percent yield of the reaction is 82.5%
Explanation:
Let's work with moles to get the percent yield.
Mass / Molar mass =
652.5 g / 158.03 g/m = 4.13 moles
If the theoretical yield of the reaction is 5 moles but we only made 4.13 moles, the percent yield will be:
(Produced yield / Theoretical yield) . 100 =
(4.13 / 5) . 100 = 82.5 %
Answer:
first first row: element
second first row :compound
Long answer- 6.79166666667
Short answer- 6.791
I think that is the short answer, if not I apologize. Have a wonderful day! :)