Answer:
0.052L
Explanation:
Molarity of a substance, which refers to the molar concentration, is calculated as follows:
Molarity (M) = number of moles (mol) ÷ volume (L)
Mole = mass ÷ molar mass
Molar Mass of AgNO3 since Ag = 108, N = 14, O = 16
108 + 14 + 16(3)
= 108 + 14 + 48
= 170g/mol
Mole = 21.89 g ÷ 170g/mol
Mole = 0.129moles
Using Molarity (M) = number of moles (mol) ÷ volume (L)
Volume = number of moles ÷ molarity
V = 0.129 ÷ 2.50
V = 0.0516
To the correct significant figure i.e. 4s.f, the numerical value of volume = 0.052L
Saturated had as much solute that it can hold, supersaturated holds more than can normally be dissolved.
First write the molecular equation with states:
(NH4)2S (aq) + 2AgNO3(aq) → Ag2S (s) + 2NH4NO3
Now write a full ionic equation by separating into ions all substances that dissociate: anything (s) (g) or (l) does not dissociate
2NH4 + (aq) + S 2-(aq) + 2Ag+ (aq) + 2NO3- (aq) → Ag2S(s) + 2NH4 + (aq) + 2NO3- (aq)
To write the NET IONIC equation, inspect the full ionic equation above and delete anything that appears on both sides of the → sign:
Net ionic equation:
S 2-(aq) + 2Ag + (aq) → Ag2S(s)
Answer:The binding energy of the nitrogen nucleus is
.
Explanation:
Atomic mass of the nitrogen,
=14.00307 amu
Number of protons, Z = 7
Number of neutrons,N = Atomic mass - number of protons
=14.0037 - 7 =7.00307
Mass of proton ,![m_p=1.00728 amu](https://tex.z-dn.net/?f=m_p%3D1.00728%20amu)
Mass of neutron,![m_n=1.00866 amu](https://tex.z-dn.net/?f=m_n%3D1.00866%20amu)
![\Delta m=(Zm_p+Nm_n)-M_A=(7\times 1.00728 amu+7.00307\times 1.00866 amu)-14.00307 amu](https://tex.z-dn.net/?f=%5CDelta%20m%3D%28Zm_p%2BNm_n%29-M_A%3D%287%5Ctimes%201.00728%20amu%2B7.00307%5Ctimes%201.00866%20amu%29-14.00307%20amu)
![\Delta m=0.11160 amu](https://tex.z-dn.net/?f=%5CDelta%20m%3D0.11160%20amu)
Binding energy =![\Delta m\times c^2=0.11160 amu\times (3\times 10^8 m/s)^2=1.0044\times 10^{16} Joules](https://tex.z-dn.net/?f=%5CDelta%20m%5Ctimes%20c%5E2%3D0.11160%20amu%5Ctimes%20%283%5Ctimes%2010%5E8%20m%2Fs%29%5E2%3D1.0044%5Ctimes%2010%5E%7B16%7D%20Joules)
![1.0044\times 10^{16} Joules=6.26\times 10^{28} MeV,(1J=6.24\times 10^{12} MeV)](https://tex.z-dn.net/?f=1.0044%5Ctimes%2010%5E%7B16%7D%20Joules%3D6.26%5Ctimes%2010%5E%7B28%7D%20MeV%2C%281J%3D6.24%5Ctimes%2010%5E%7B12%7D%20MeV%29)
The binding energy of the nitrogen nucleus is
.