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SVETLANKA909090 [29]
3 years ago
8

Fill in the blanks to create the lesson question,

Chemistry
2 answers:
baherus [9]3 years ago
8 0

Answer:

Pressure

Explanation:

Klio2033 [76]3 years ago
6 0

Answer:pressure

Explanation:

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15. Calculate the hydrogen ion concentration of a
deff fn [24]

Answer:

Explanation:

pH = − log [H+] , we can solve for [H+] as,

− pH = log [H+] ,

[H+] = 10^−pH,

so PH =2.4 in you case is

[H+] = 10^-2.4 =0.00398

The option are not correct it looks

4 0
3 years ago
a swimming pool is 50 meters long. each day a swimmer swam total of 75 lengths of the pool for practice. how many kilometers did
Brilliant_brown [7]
50x75=3750 -- metres per day
3750x15=56250 -- metres in 15 days

Divide by 1000 to convert to km
56.250km
<u>56.25km</u>
8 0
3 years ago
4. A student purified a 500-mg sample of phthalic acid by recrystallization from water. The published solubility of phthalic aci
kupik [55]

Answer:

2.77 mL of boiling water is the minimum amount which will dissolve 500 mg of phthalic acid.

Explanation:

We know from the problem that 18 g of phthalic acid are dissolved in 100 mL of water at 99 °C.

Now we devise the following reasoning:

If          18 g of phthalic acid are dissolved in 100 mL of water at 99 °C

Then   0.5 g of phthalic acid are dissolved in X mL of water at 99 °C

X = (0.5 × 100) / 18 = 2.77 mL of water

7 0
3 years ago
Examine the statement.
saveliy_v [14]
My view point is that i disagree and that the rules are completely different
6 0
3 years ago
Consider the reaction. mc014-1.jpg How many grams of methane should be burned in an excess of oxygen at STP to obtain 5.6 L of c
garri49 [273]
The reaction for the combustion of methane can be expressed as follows.
                           CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
                            moles of CO2 = (5.6 L) / (22.4 L/1 mole)
                             moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
                              moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
                                                    = 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane. 
5 0
4 years ago
Read 2 more answers
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