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Sophie [7]
3 years ago
8

Which are compounds, which are elements and which are mixtures?

Chemistry
1 answer:
Kamila [148]3 years ago
5 0

Answer:

first first row: element

second first row :compound

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The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles
Oliga [24]

Answer:

K = [ HOCl ] . [HgO. HgCl2] / [Cl2]^2 [H2O] [HgO]^2

Explanation:

The law of Mass Action states that, at constant temperature, the rate of reaction is proportional to the active masses of each of the reactants.

The reaction above is a reversible reaction and the law of mass action also applies to it.

The rate of reaction from left-to-right reaction = r1 = k. [Cl2]^2 [H2O] [HgO]^2

Rate of reaction from right - to - left r2 = k. [hocl]^2 [HgO . hgcl2]

Then at equilibrium,

r1 = r2

k1/k2 = [HOCl ]^2 [HgO. HgCl2] / [Cl2]^2 [H2O] [HgO]^2 = K

where K is the equilibrium constant for the reaction.

5 0
3 years ago
Using a ph meter, you find the ph of an unknown solution to be 8. 0. How would you describe this solution?.
insens350 [35]

Answer:

Just Barely Base/Neutral

Explanation:

a pH of 8.0 is greater than Neutral (7.0) but is still neutral due to it being more neutral than a base

4 0
2 years ago
Escriba 4 ideas sobre que sucede cuando la radiación solar llega a la tierra​
poizon [28]

Answer:

La radiación UV-B es parcialmente absorbida por el ozono y llega a la superficie de la tierra, produciendo daño en la piel. Ello se ve agravado por el agujero de ozono que se produce en los polos del planeta.

Explanation:

3 0
2 years ago
The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
3 years ago
What material would be the best choice for the support beams of a building
Natasha2012 [34]
Steel would be the best choice for support beams
5 0
3 years ago
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