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brilliants [131]
4 years ago
11

Consider the following system of equations:

Mathematics
2 answers:
Temka [501]4 years ago
7 0

Answer:

Step-by-step explanation:

Using substitution method of simultaneous equation,

2x + 3y = 45 ___________(1)

x + y = 10 ___________(2)

From equation 2 solve for x to produce equation 3

x = 10 - y ______________(3)

Now put equation 3 or rather substitute for x in equation 1

2( 10 - y )+ 3y = 45

Solve the equation now

2x10 -2 X y + 3y =45

20 -2y +3y = 45

y = 45 - 20

y = 25

To get x, substitute for y in equation 3

x = 10 - 25

x = -15

Therefore,

x = -15.

,To check.

Put x=-15 and y = 25 in equation

x +y = 10

-15 +25 = 10.

Therefore, x = -15.

Kobotan [32]4 years ago
5 0

Answer:

x=-15, y=25. (-15, 25).

Step-by-step explanation:

2x+3y=45

x+y=10

--------------

x=10-y

2(10-y)+3y=45

20-2y+3y=45

20+y=45

y=45-20

y=25

x+25=10

x=10-25

x=-15

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Read 2 more answers
Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).
zzz [600]

Answer:

F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

Step-by-step explanation:

We have given F(S)=\frac{7e^{-7s}}{s^2-49}

Now  F(S)=e^{-7s}G(s)

Here G(S)=\frac{7}{S^2-49}

Now first find the Laplace inverse of G(S)

Using partial fraction

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7=A(S-7)+B(S+7)

On comparing the coefficient

A=\frac{1}{2}  and B=\frac{-1}{2}  

On putting the value of A and B  

G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}

Taking inverse Laplace

G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}

Now in G(s) there is onether term e^{-7s}

So F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

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