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brilliants [131]
3 years ago
11

Consider the following system of equations:

Mathematics
2 answers:
Temka [501]3 years ago
7 0

Answer:

Step-by-step explanation:

Using substitution method of simultaneous equation,

2x + 3y = 45 ___________(1)

x + y = 10 ___________(2)

From equation 2 solve for x to produce equation 3

x = 10 - y ______________(3)

Now put equation 3 or rather substitute for x in equation 1

2( 10 - y )+ 3y = 45

Solve the equation now

2x10 -2 X y + 3y =45

20 -2y +3y = 45

y = 45 - 20

y = 25

To get x, substitute for y in equation 3

x = 10 - 25

x = -15

Therefore,

x = -15.

,To check.

Put x=-15 and y = 25 in equation

x +y = 10

-15 +25 = 10.

Therefore, x = -15.

Kobotan [32]3 years ago
5 0

Answer:

x=-15, y=25. (-15, 25).

Step-by-step explanation:

2x+3y=45

x+y=10

--------------

x=10-y

2(10-y)+3y=45

20-2y+3y=45

20+y=45

y=45-20

y=25

x+25=10

x=10-25

x=-15

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Answer:

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Step-by-step explanation:

Since there is no picture attached to depict the house and its dimension, I am taking values of a similar problem.

<em><u>Dimensions of Shed</u></em>

2 walls with dimensions of 15 ½ ft. by 12 ft.

2 walls with dimensions of 25 ¼ ft. by 12 ft.

Ceiling with dimensions of 15 ½ ft. by 25 ¼ ft.

2 windows that are each 2 ft. by 4½ ft. as well as an 8-ft. by 5-ft. door

<u>Solution</u>

We need to find the total wall area and ceiling area which when combined will give us the total area shed's outer surface that needs to be painted.

For total area of the wall, we need to first find the sum of area for each wall and subtract area of windows and door

Wall Area = Area of 1st two walls+Area of other two walls-Area of 2 windows-Area of door=[15.5(12)(2)] + (25.25) (12) (2) - (2)(2) (4.5) -(8)(5)

Wall Area = 371 + 606 - 17 - 40

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Ceiling Area is just the area of the ceiling

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Ceiling Area = 391.375 square ft= 43.486 square yard

<u>Total Area = Wall Area+Ceiling Area </u>=102.2+43.486=145.7 Square yards

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<em>Note: Converted Square foot to square yard as the problem requires that.</em>

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Question:  The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.82.

a. If the probability that a student owns both is 0.55, what is the probability that a randomly selected student owns a car or computer?

b. What is the probability that a randomly selected student does not own a car or computer?

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(b) 0.08

Step-by-step explanation:

(a)

Applying

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Where A represent Car, B represent Computer.

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(b)

Applying

Pr(A or B) = 1 – Pr(not-A and not-B)

Pr(not-A and not-B) = 1-Pr(A or B) ..................... Equation 2

Given: Pr(A or B)  = 0.92

Substitute these value into equation 2

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