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padilas [110]
3 years ago
9

How is finding the factors of a number different from finding the prime factorization of a number?

Mathematics
1 answer:
Serjik [45]3 years ago
6 0
Factors are any numbers (prime or composite) that go into a given number. Prime factorization is finding all the prime numbers that go into the number and how many times each prime number goes into it. For example, factors of 16 are: 1, 2, 4, 8, 16. The prime factorization of 16 is: 2*2*2*2.
Another example:
Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42
Prime factorization of 42: 2*3*7
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Becca has 115 students. Susana has 8 fewer students than Becca. Erika has 25 more students than Susana. How many students does S
Olegator [25]

Answer:

Susana will have 107 students.

Step-by-step explanation:

Becca have students = 115

  • Susana has 8 fewer students than Becca.

We can write its as:

Becca has 115 students, so Susana will have 115-8 = 107 students

Because fewer means less than so, 8 less than 115 is 115-8

  • Erika has 25 more students than Susana.

We can write it as:

Susana has 107 students, so Erika will have: 107+25 = 132 students.

because more means we need to add 25 students with number of students in Susana class.

So, Susana will have 107 students.

4 0
3 years ago
Wal-mart sells a case of 24 cans of Diet Coke for $6.88. Kroger sells a 12 pack of Diet Coke for $3.99. Determine the unit rate
ra1l [238]

Answer:

Wal-mart

Step-by-step explanation:

Given data

Wal-mart sells a case of 24 cans of Diet Coke for $6.88

unit price

=$6.88/24

=$0.29

Kroger sells a 12 pack of Diet Coke for $3.99

unit price

=$3.99/12

=$0.33

Hence the best buy is Wal-mart

7 0
3 years ago
Pls Help :(((
Lelechka [254]

\text{Let,}\\\\~~~~~~~a^x =b^y = c^z = k\\\\\text{So,}\\ \\a = k^{\dfrac 1x}\\\\b=k^{\tfrac 1y}\\\\\ c = k^{\tfrac1z}\\\\\text{Now, given that,}\\\\~~~~~~~~~b^2 = ac\\\\\implies \left( k^\tfrac 1y \right)^2 = k^{\tfrac 1x} \cdot k^{\tfrac 1z}\\\\\implies k^{\tfrac 2y} = k^{\tfrac 1x + \tfrac 1z} ~~~~~~~~~~;[a^m \cdot a^n = a^{m+n}]\\\\\implies \dfrac 2y = \dfrac 1x + \dfrac 1z\\\\\implies \dfrac 1x + \dfrac 1z = \dfrac 2y \\\\\text{Proved.}

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2 years ago
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lana [24]
I’m not sure but I hope this helps

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