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3 years ago

How is finding the factors of a number different from finding the prime factorization of a number?

1 answer:

6 0

Factors are any numbers (prime or composite) that go into a given number. Prime factorization is finding all the prime numbers that go into the number and how many times each prime number goes into it. For example, factors of 16 are: 1, 2, 4, 8, 16. The prime factorization of 16 is: 2*2*2*2.
Another example:
Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42
Prime factorization of 42: 2*3*7

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(Distribute , then simplify the remaining expression. Final answer must be in standard form) Please help !!

Sergeu [11.5K]

Problem 22
$4x^2(2x^2+x-5) - x(x^3+5x^2-3) + 17$
$4x^2(2x^2)+4x^2(x)+4x^2(-5) - x(x^3)-x(5x^2)-x(-3) + 17$
$8x^4+4x^3-20x^2 - x^4-5x^3+3x + 17$
$7x^4-x^3-20x^2+3x + 17$

So the final simplified answer to problem 22 is
$7x^4-x^3-20x^2+3x + 17$

--------------------------------

Problem 23
$-2x(x^3-6x^2+6)+4x^3-(5x^4+10x)$
$-2x(x^3)-2x(-6x^2)-2x(6)+4x^3-(5x^4)-(10x)$
$-2x^4+12x^3-12x+4x^3-5x^4-10x$
$-7x^4+16x^3-22x$

So problem 23 simplifies to
$-7x^4+16x^3-22x$

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Problem 24
$4b[2a^2-5(3ab-2b^2)]+29ab^2$
$4b[2a^2-5(3ab)-5(-2b^2)]+29ab^2$
$4b[2a^2-15ab+10b^2]+29ab^2$
$4b[2a^2]+4b[-15ab]+4b[10b^2]+29ab^2$
$8a^2b-60ab^2+40b^3+29ab^2$
$8a^2b-31ab^2+40b^3$

So problem 24 simplifies to
$8a^2b-31ab^2+40b^3$

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Problem 25
$2y(6x-4x^2y)+13x^2y^2-6$
$2y(6x)+2y(-4x^2y)+13x^2y^2-6$
$12xy-8x^2y^2+13x^2y^2-6$
$12xy+5x^2y^2-6$

The final answer for problem 25 is
$12xy+5x^2y^2-6$

8 0

3 years ago

The complement of an angle is 30∘ less than twice the angle. Find the angle.<br><br> degrees

WINSTONCH [101]

The answer is 50 i think

4 0

2 years ago

A compressed air tank carried by scuba divers has a volume of 8.00 L and a pressure of 141 atm at 22.0°C. What is the volume (in

weqwewe [10]

Answer:

Volume of air in the tank =1,044 Liter

Step-by-step explanation:

Given:

Tank volume = 8 Liter

Pressure = 141 atm

Temperature = 22°C = 273° + 20° = 295° K

Find:

Volume of air in the tank = ?

Computation:

$\frac{Pressure\times Tank\ volume}{Tempreture} =\frac{Pressure\times Air\ volume}{Tempreture}\\\\\frac{141\times 8}{295} =\frac{1\times Air\ volume}{273.15}\\\\\frac{1,128}{295} =\frac{Air\ volume}{273.15}\\\\Air\ volume=1,044.45$

Volume of air in the tank =1,044 Liter

8 0

3 years ago

The cost of a school banquet is 75$ plus 15$ per person.

ivann1987 [24]

Answer:

The cost of a school banquet is $75+30n, where n is the number of people attending.

If 53 people are attending to visit school banquet, then you have to find the value of given expression at n=53.

At n=53, the value is $(75+30·53)=$1,665.

Step-by-step explanation:

4 0

2 years ago

6(u+3) Use the distributive property to remove the parentheses 6(u+3

Vlad [161]

Answer:

6u+18

Step-by-step explanation:

6*u=6u and 6*3=18

8 0

2 years ago