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3 years ago

What is the slope of the line defined by the equation shown below ? 2x+3y+23=0

Mathematics

2 answers:

nordsb [41]3 years ago

6 0

Hi there!

I think the slope of the line crossing over the graph is negative.

Why?

Because y=−0.666667x−7.666667 OR, read below!

We will get a negative answer, to show that our slope is negative.

We'll solve for y instead of x.

2x + 3y + 23 = 0

1) Add -23 to both sides. (We're already starting out with a negative!)

2x + 3y + 23 + −23 = 0 + −23

2x + 3y = −23

2) Add -2x to both sides.

2x + 3y + −2x = −23 + −2x

3y = −2x − 23

3) Divide both sides by 3.

3y/3 = -2x - 23/3

y = -2/3x + -23/3

So, now that we've done all 3 steps, your answer is

y = -2/3x + -23/3, which is a negative answer!

Now we see that the slope of 2x+3y+23=0 is negative.

Hope this helps! :D

Meant to add - The /'s are fraction bars

adell [148]3 years ago

5 0

Slope = -1.333/2.000 = -0.667 x-intercept = -18/2 = -9 y-intercept = -18/3 = -6

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1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

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Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
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In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

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$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

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I hope this helps you

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