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valentina_108 [34]
3 years ago
15

Need help ASAP, tysm

Mathematics
2 answers:
MAVERICK [17]3 years ago
6 0
You combine like terms.

+ 6a
+ 5a
+ 2a
- 1a
___

12a.

there is a negative 5 left, so the standard form is:

12a - 5.

hope this helps! ❤️
n200080 [17]3 years ago
4 0

Answer:

12a-5

Step-by-step explanation:

add like terms

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ONLY NUMBER 1 please help
yan [13]

Answer:

Just to be on the safe side the first #1 is 31.5 and the second #1 is 57.82

5 0
3 years ago
Read 2 more answers
Need help due tomorrow
nika2105 [10]
250cm^2

To find the area of shape B we need to find the factor by which you multiply to get from 12 to 15. To find this we divide 15 by 12 to get 1.25. We now multiply the area of shape A (200) by the factor 1.25 to get the answer. The answer is 250cm^2.

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.
3 0
3 years ago
Find f(-2) f(x)=9x^2-5x+2
borishaifa [10]

Find f(-2) f(x)=9x^2-5x+2


f(-2) means replace x in the equation with -2:


f(-2)=9(-2)^2-5(-2)+2

= 9(4) +10 + 2

= 36 +10 + 2

= 48


f(-2) = 48



4 0
3 years ago
What's the product of 3 2/3 and 14 2/5 ?<br> A. 52 4/5<br> B. 52 4/15<br> C. 54<br> D. 42 4/5
wlad13 [49]

Answer:

52 4/5

Have a nice day! :)

4 0
3 years ago
Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB
Digiron [165]

Answer: The distace between midpoints of AP and QB is \frac{a}{8}.

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = \frac{AP}{2}

QB = \frac{AP}{2}

Substituing:

AP + 2*(\frac{AP}{2}) = a

2AP = a

AP = \frac{a}{2}

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = \frac{AP}{2}

QB = \frac{a}{2}*\frac{1}{2}

QB = \frac{a}{4}

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}

\frac{AP}{2} = \frac{a}{4}

<u>Midpoint of QB</u>:

\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}

\frac{QB}{2} = \frac{a}{8}

The distance is:

d = \frac{a}{4} - \frac{a}{8}

d = \frac{a}{8}

4 0
3 years ago
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