Determine the percent ionization of a 0.145 m hcn solution.

1 answer:

5 0

When Ka of HCN = 6.2x10^-10

HCN H3O+ CN-
initial 0.145 0 0
change -X +X +X
final (0.145-X) +X +X

Ka= [H3O+][CN]- / [HCN]
by substitution:
we can assume [HCN] = 0.145
6.2x10^-10 = X*X / (0.145) by solving this equation,
X = 9.5 x 10^-6
∴ [ H3O+] = 9.5 X 10^-6
∴percent ionization = [H3O+]/[HCN] *100
= 9.5X10^-6 / 0.145 *100
= 0.0066 %

You might be interested in

Please help me with this question I will make you brainliest!! SCIENCE

schepotkina [342]

Answer:

A skateboarder coming down the ramp.

When something is going up against ( up or <u><em>down</em></u> ) something it causes friction.

Hope this helps!

5 0

3 years ago

1. The electron arrangement ions X and Y2 are 2, 8, and 2, 8, 8 respectively.

svetoff [14.1K]

The given question is incomplete. the complete question is:

The electron arrangement ions $X^{3+}$ and $Y^{2-}$ are 2, 8, and 2, 8, 8 respectively.

Write the electronic arrangement of the elements X and Y.

Write the formula of the compound that would be formed between X and Y.

Answer: 1. The electronic arrangement for X and Y are 2,8, 3 and 2,8,5 respectively.

The formula of the compound formed is $X_2Y_3$

Explanation:

Electronic configuration is the arangement of electrons in an atom in order of increasing energies.

Cations are formed when electrons are lost by atoms and anions are formed when electrons are gained by atoms.

$X^{3+}:2,8$

$X:2,8,3$

$Y^{3-}:2,8,8$

$Y:2,8,5$

For formation of a neutral ionic compound, the charges on cation and anion must be balanced.

Here element X is having an oxidation state of +3 called as $X^{3+}$ cation and $Y^{2-}$ is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $X_2Y_3$

3 0

3 years ago

The density of a gas is 1.35 L what is the volume of the gas when the mass is 12.5 g

mart [117]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$