3. is the correct option listed above.
Answer:
Calcium salts give bone its a. tensile strength. b. torsional strength. c. flexibility. d. compressional strength.
The answer is Option D (Compressional strength)
Explanation:
Calcium is the most abundant mineral in the body, most of the calcium in the body are found in the bones and teeth. Calcium helps the body with not only building strong bones and teeth, but also assisting the body in sending and receiving nerve signals. If blood calcium gets too high or too low, the muscles and nerves will not function.
Bone which serves as a storage area for calcium are mostly made of the protein collagen, forms the skeletal framework of all vertebrates, and it plays a major role in calcium balance in the blood. Bone exhibits four types of cells: osteoblasts, bone lining cells, osteocytes, and osteoclasts. Functions of bone includes structural support of the body, protection of internal organs, attachment of the muscles, production of blood cells.
Calcium salts form crystals that give bones great strength. Bone mineral is formed from carbonated hydroxyapatite. Calcium hydroxyapatite is a naturally occurring mineral form of calcium apatite, it contains magnesium and carbonate and it is identical to the substance in teeth and bones. The collagen fibers give bone its tensile strength, and hydroxyapatite give bone its compressive strength.
the Equator receives the most solar energy
A scale and a ruler. The scale to measure the mass, and a ruler to measure the volume.
The question is incomplete, complete question is :
Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (
for HF is 
.)
[HF] = 0.280 M
Express your answer to two decimal places.
Answer:
The pH of an 0.280 M HF solution is 1.87.
Explanation:3
Initial concentration if HF = c = 0.280 M
Dissociation constant of the HF = 
Initially
c 0 0
At equilibrium :
(c-x) x x
The expression of disassociation constant is given as:
![K_a=\frac{[H^+][F^-]}{[HF]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH%5E%2B%5D%5BF%5E-%5D%7D%7B%5BHF%5D%7D)
Solving for x, we get:
x = 0.01346 M
So, the concentration of hydrogen ion at equilibrium is :
![[H^+]=x=0.01346 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dx%3D0.01346%20M)
The pH of the solution is ;
![pH=-\log[H^+]=-\log[0.01346 M]=1.87](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D%3D-%5Clog%5B0.01346%20M%5D%3D1.87)
The pH of an 0.280 M HF solution is 1.87.
