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Svetradugi [14.3K]

4 years ago

9

A scientist uses an accelerator and high energy electrons to study the particles inside the protons of a helium atom. What parti

cles is the scientist studying? A. the He neutrons B. the He nucleus C.the He electrons D.the He quarks

1 answer:

marissa [1.9K]4 years ago

6 0

<span>B. the He nucleus C.the He electrons D.the He quarks</span>

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What is frost action

attashe74 [19]

The weathering process caused by cycles of freezing and thawing of water in surface pores, cracks, and other openings

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3 years ago

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Which of the following is an electrolyte?<br><br> a. PbCl2<br> b. MgS<br> c. HNO3<br> d. Al2(Cr2O7)3

Phoenix [80]

Answer: A: PbCl2

Hope dis helps!

8 0

3 years ago

CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7

padilas [110]

<u>Answer:</u> The $\Delta G$ for the reaction is 54.425 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

$CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)$

We are given:

$\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol$

To calculate $\Delta G^o_{rxn}$ for the reaction, we use the equation:

$\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]$

For the given equation:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J$

Conversion factor used = 1 kJ = 1000 J

The expression of $K_p$ for the given reaction:

$K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}$

We are given:

$p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm$

Putting values in above equation, we get:

$K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85$

To calculate the gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_p$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = $8.314J/K mol$

T = Temperature = $25^oC=[25+273]K=298K$

$K_p$ = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

$\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol$

Hence, the $\Delta G$ for the reaction is 54.425 kJ/mol

7 0

3 years ago

For case 1, what happens when an electron jumps from energy level 1 to energy level 3 in an atom?

BaLLatris [955]

Answer:

Case 1 (energy level): In an atom, an electron jumps from energy level 1 to energy level 3. ... The energy will increase.

Explanation:

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3 years ago

28 grams of Al react with 30 Oxygen gas (O2) to produce Al Oxide (Al2O3). How many grams of Al Oxide will be produced

Kamila [148]

Answer:

58

Explanation:

Due to conservation of energy, the sum of the reactants = the sum of the products. So 28 + 30 = 58g

8 0

3 years ago