Answer:
Empirical formula is CH₄
Molecular formula = C₂H₈
Explanation:
Mass of carbon = 37.5 g
Mass of hydrogen = 12.5 g
Molecular weight = 32 g/mol
Molecular formula = ?
Empirical formula = ?
Solution:
Number of gram atoms of C = 37.5 g /12g/mol = 3.125
Number of gram atoms of H = 12.5 g / 1.008 g/mol= 12.4
Atomic ratio:
C : H
3.125/3.125 : 12.4 /3.125
1 : 4
C : H : = 1 : 4
Empirical formula is CH₄
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
n = 32 / 16
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 ( CH₄)
Molecular formula = C₂H₈
The mass number of an atom : 26
<h3>Further explanation</h3>
Given
12 protons, 14 neutrons, and 12 electrons
Required
The mass number
Solution
Inside the atom there are 3 sub-particles, namely protons, neutrons and electrons. Protons and electrons are present in the atomic nucleus while electrons move around the atomic nucleus through energy levels in the atomic shell
Atomic number = number of protons = number of electrons
Mass number = number of protons + number of neutrons
Input the value :
Mass number = 12 + 14
Mass number = 26
Answer:
38.8 mL
Explanation:
2CO(g) + O₂(g)⟶2CO₂(g)
Because pressure and temperature remain constant, we can <em>think of the moles ratios as volume ratios</em>. This means that 2mL of CO react with 1 mL of O₂ to produce 2 mL of CO₂.
Because the problem asks us to calculate the amount of oxygen gas unreacted, then CO is the limiting reactant. We <u>calculate the amount of O₂ that reacted</u>, from the available amount of CO:
82.4 mL CO * 
= 41.2 mL O₂
Thus, the oxygen gas remaining is:
80.0 mL - 41.2 mL = 38.8 mL O₂
