Answer:
Explanation:
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In this case, since the dilution processes are characterized by the decrease of the original stock solution by holding the moles constant and therefore modify the volume, for the described dilution we can write:
Whereas we are asked to compute the volume of the original solution; thus, we can solve for it as shown below:
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Answer:
11.54 M
Explanation:
In this case, all we have to do is to apply the following expression:
M = n/V
M: molarity
n: moles
V: volume of solution in liters
In this case, we can assume that the volume of water will be the volume of solution. This is because the problem is not specifing if the moles of AgNO3 are liquid or solid, so we can make a safe assumption of the volume.
Using the expression above we have:
M = 5.54 / 0.48
M = 11.54 M
This is the molarity of solution
