All categories

3 years ago

What's the greatest number of pill bugs found

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

6 0

Yea do you have anything that can show for the question then I might help with your questions:)

You might be interested in

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

A toy plane moves at a constant speed of 2m/s. How long will it travel a distance of 42 meters?

Tpy6a [65]

Answer:

option A. 21 sec

Step-by-step explanation:

Speed = the distance over the time

Given:

Speed = 2 m/s and distance = 42 m and time = t

So,

2 = 42/t

Solve for t

t = 42/2 = 21 sec.

The answer is option A. 21 sec

7 0

3 years ago

The distance from Houston to

marissa [1.9K]

Answer:

distance from Houston to Galveston in kilometers will be: 80km

Step-by-step explanation:

Given

The distance from Houston to Galveston is about 50 miles.

i.e.

Kilometers in 1 Mile = 1.6 km

As the distance from Houston to Galveston is about 50 miles, so

The distance from Houston to Galveston in kilometers will be:

50(1.6) = 80 ∵ Kilometers in 1 Mile = 1.6 km

Therefore,

The distance from Houston to Galveston in kilometers will be: 80km

8 0

3 years ago

Calculate the length of the unknown side of this right angled triangle

azamat

Answer:

12.04

Step-by-step explanation:

Well to solve for the unknown side "c" we need to use the Pythagorean Theorem formula,

$a^2 + b^2 = c^2$

We already have a and b which are 8 and 9 so we plug them in.

$(8)^2 + (9)^2 = c^2$

64 + 81 = c^2

145 = c^2

c = 12.04 rounded to the nearest hundredth.

Thus,

the unknown side is about 12.04.

Hope this helps :)

8 0

3 years ago

Please help me I need help

Luba_88 [7]

Answer:

$|28 - x| = 0 \\ 28 - x = 0 \\ - x = - 28 \\ x = 28$

3 0

3 years ago

Read 2 more answers