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goblinko [34]
3 years ago
10

Can two numbers have a GCF that is bigger than their LCM? Explain how you know?

Mathematics
1 answer:
DiKsa [7]3 years ago
7 0
The answer to this question would be: No, they can't

Greatest common factor biggest possible value is the number value itself. There is no factor that bigger than the number.

But the least common multiple smallest possible value is the number. There is no multiple that smaller than the number.

So it is not possible to have GCF bigger than LCM.

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How do you turn 53 1/3 into a fraction????
goldfiish [28.3K]
160/3 is 53 1/3 as a fraction

7 0
3 years ago
Read 2 more answers
Which of the following shows the division problem below in synthetic division
alexandr402 [8]

Answer:

The Answer is C

Step-by-step explanation:

Look at each coefficient next to the degree of the radical. When inputting that number for synthetic division (From greatest degree to least) you would get 8 1 and -5. The number that is the divisor is the 6, but you have to set (x - 6) to equal zero, which would get you a number of 6.

7 0
3 years ago
Read 2 more answers
Ames wants to informally prove the converse of the Pythagorean Theorem by producing some evidence that supports it.
Mazyrski [523]

Answer:

The second and fourth one is right

Step-by-step explanation:

A²+ B² = C²

15² + 20² = 25²

225 + 400 = 625

625 = 625

16² + 30² = 34²

256 + 900 = 1156

1156 = 1156

They both check out

3 0
3 years ago
- Given a test statistic of t= 3.018 of a left-tailed test with n= 13, use a 0.01 significance level
alina1380 [7]

Using the t-distribution, it is found that the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the mean of a given population is equal to 85, that is:

H_0: \mu = 85

We have a left-tailed test, hence, at the alternative hypothesis, it is tested if the mean of the population is less than 85, that is:

H_1: \mu < 85

<h3>What is the decision?</h3>

The test statistic is of t = -3.018.

Using a t-distribution calculator, with test statistic t = -3.018, 13 - 1 = 12 df and a significance level of 0.01, it is found that the p-value for a left-tailed test is of 0.0051.

The p-value is <u>less than 0.01</u>, hence the null hypothesis is rejected and the correct option is:

0.005 < P-value < 0.01, reject the null hypothesis.

More can be learned about the t-distribution at brainly.com/question/16313918

5 0
2 years ago
A1.0 kg cart moving right at 5.0 -- on a frictionless track
bulgar [2K]

Answer:

3.0 kg

Step-by-step explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(1.0 kg) (5.0 m/s) + m (-2.0 m/s) = (1.0 kg) (-4.0 m/s) + m (1.0 m/s)

5.0 kg m/s + m (-2.0 m/s) = -4.0 kg m/s + m (1.0 m/s)

9.0 kg m/s = m (3.0 m/s)

m = 3.0 kg

6 0
3 years ago
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