An airplane is flying at a height of 5 kilometers above the ground. The distance along the ground from the airplane to the airport is 7 kilometers. What is the angle of depression from the airplane to the airport? (Write the answer to the nearest degree.)
✞ Step 1 ✞: Identify what is asked in the problem.
❒ The angle of depression from the airplane to the airport.
✞ Step 2 ✞: Use appropriate trigonometric ratio to solve the problem.
❒ Since the two legs of the right triangle are part of the problem, hence we use tangent ratio:
✞ Step 3 ✞: Solution and interpretation.
Hence, the angle of depression from the airplane to the airport is approximately 36°.
Answer:
ok
Step-by-step explanation:
Answer:
Radius of a circle= ![\sqrt[2]{17} m](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B17%7D%20m)
Step-by-step explanation:
As we know, area of a circle=π x 
So give area= 68π
= 68π=π x
Simplify ( Cancel the similar signs)
= = 68
= r = 
=
= r =
Hope it helps
Peace
And a brainliest would be really appreciated
Answer:
The answer is 0
Anything that ends up being divided by zero is always zero.
Answer:
a) t = 0.54 seconds
b) t = 8 seconds
Step-by-step explanation:
Given in the question the equation
h = 40t - 5t²
<em> where h is height in meters</em>
<em> t is time in seconds</em>
<em />
Time it took to reach 20 meters
20 = 40t - 5t²
-5t² + 40t - 20 = 0
by using quadratic formula for factorisation
<h3>t = (-b± √(b)² - 4(a)(c) ) / 2(a)</h3>
t = 0.54 (upward motion)
or
t = 7.46 (downward motion)
b) Time it took to reach the ground
at ground h = 0
So,
0 = 40t - 5t²
t(40 - 5t ) = 0
t = 0 (at starting point)
or
40 -5t = 0
5t = 40
t = 40 /5
t = 8 seconds
