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VARVARA [1.3K]
3 years ago
7

I am stuck on this question of knowing how to break it down to get the answer

Mathematics
1 answer:
maksim [4K]3 years ago
7 0
3 x 3 - ( (-1)^2 - 2)^2

Start evaluating the one in the most inner bracket:
3 x 3 - ( (-1)^2 - 2)^2
= 3 x 3 - (1 - 2)^2

There is one more bracket, so we do what is in the bracket:
3 x 3 - ( (-1)^2 - 2)^2
= 3 x 3 - (1-  2)^2
= 3 x 3 - (-1)^2
= 3 x 3 - 1

Between x and -, we do the x first:
3 x 3 - ( (-1)^2 - 2)^2 
= 3 x 3 - (1-  2)^2
= 3 x 3 - (-1)^2
= 3 x 3 - 1
= 9 - 1

Then we do the -:
3 x 3 - ( (-1)^2 - 2)^2
= 3 x 3 - (1-  2)^2
= 3 x 3 - (-1)^2
= 3 x 3 - 1
= 9 - 1
= 8

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If a cup of coffee has temperature 97°C in a room where the ambient air temperature is 25°C, then, according to Newton's Law o
FinnZ [79.3K]

Answer:

The  average temperature  is T_{a} = 81.95^oC

Step-by-step explanation:

From the question we are told that

    The temperature of the coffee after time t is   T(t) =  25 + 72 e^{[-\frac{t}{45} ]}

Now the average temperature during the first 22 minutes i.e fro 0 \to  22minutes is mathematically evaluated as

              T_{a} =  \frac{1}{22-0}  \int\limits^{22}_{0} {25 +72 e^{[-\frac{t}{45} ]}} \, dx

               T_{a} = \frac{1}{22} [25 t  +  72 [\frac{e^{[-\frac{t}{45} ]}}{-\frac{1}{45} } ] ] \left| 22} \atop {0}} \right.

             T_{a} = \frac{1}{22} [25 t  - 3240e^{[-\frac{t}{45} ]} ] \left | 45} \atop {{0}} \right.

              T_{a} = \frac{1}{22} [25 (22)  - 3240e^{[-\frac{22}{45} ]}   - (- 3240e^{0} )]

            T_{a} = \frac{1}{22} [550  - 1987.12  +  3240]

          T_{a} = 81.95^oC

       

8 0
2 years ago
Solve in simplest form<br><br> 15 3/5 - 3 2/7
artcher [175]

Answer:

12 11/35

Step-by-step explanation:

Given Data

First term= 15 3/5

To simple fracrion= 78/5

Second term= 3 2/7

To simple fracrion= 23/7

Hence the operation goes thus

= 78/5- 23/7

LCM = 35

=546-115/35

=431/35

=12 11/35

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3 years ago
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3 0
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Answer:

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Step-by-step explanation:

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