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algol [13]
3 years ago
9

Chad created a table that shows the ratio of his role playing game cards.

Mathematics
2 answers:
Leona [35]3 years ago
8 0
The real correct answer will be A
marissa [1.9K]3 years ago
3 0

Answer:

it is A

Step-by-step explanation:

the reason why is because i took the quiz and I got a A+

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What is the solution to this system of equations?
laiz [17]

Answer:

Step-by-step explanation:

Solving by elimination and substitution:

x + y = 7

x − y = − 3

on adding the two equations  

y  gets cancelled

x + y = 7

x − y = − 3

2 x = 4

x = 4 2 = 2

substituting this value of x  

in equation 1:

x +y = 7

2 + y = 7

y = 7 − 2

y = 5

the solution for the system of equations are :

x = 2

y = 5

Hope it helps pls mark as brainliest

4 0
3 years ago
Read 2 more answers
Nine times a number decreased by 16
Setler79 [48]

Answer:

9 · x - 16

Explanation:

Nine times a number: 9 · x

Decreased by 16: - 16

Put them together: 9 · x - 16

7 0
3 years ago
(3,2),(5,7),(1,4),(9,2),(3,7)<br> Domain and range
Tatiana [17]

Answer:

If I remember correctly-

3,5,1,9,3 : domain

2,7,4,2,7 : range

5 0
3 years ago
Read 2 more answers
How do I do this -9 - 16m = 7? What are the steps?
nordsb [41]

m = -1

Step-by-step explanation:

-16m = 7 + 9

-16m = 16

m = 16 ÷ -16

m = -1

4 0
3 years ago
what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube
Dmitrij [34]
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

\frac{99}{2} (2x+98)=p^3 \\  \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}

By substitution, we have that p=33 and x=314.

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
3 0
3 years ago
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