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3 years ago

Chad created a table that shows the ratio of his role playing game cards.

Mathematics

2 answers:

Leona [35]3 years ago

8 0

The real correct answer will be A

marissa [1.9K]3 years ago

3 0

Answer:

it is A

Step-by-step explanation:

the reason why is because i took the quiz and I got a A+

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What is the solution to this system of equations?

laiz [17]

Answer:

Step-by-step explanation:

Solving by elimination and substitution:

x + y = 7

x − y = − 3

on adding the two equations

y gets cancelled

x + y = 7

x − y = − 3

2 x = 4

x = 4 2 = 2

substituting this value of x

in equation 1:

x +y = 7

2 + y = 7

y = 7 − 2

y = 5

the solution for the system of equations are :

x = 2

y = 5

Hope it helps pls mark as brainliest

4 0

3 years ago

Read 2 more answers

Nine times a number decreased by 16

Setler79 [48]

Answer:

9 · x - 16

Explanation:

Nine times a number: 9 · x

Decreased by 16: - 16

Put them together: 9 · x - 16

7 0

3 years ago

(3,2),(5,7),(1,4),(9,2),(3,7)<br> Domain and range

Tatiana [17]

Answer:

If I remember correctly-

3,5,1,9,3 : domain

2,7,4,2,7 : range

5 0

3 years ago

Read 2 more answers

How do I do this -9 - 16m = 7? What are the steps?

nordsb [41]

m = -1

Step-by-step explanation:

-16m = 7 + 9

-16m = 16

m = 16 ÷ -16

m = -1

4 0

3 years ago

what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube

Dmitrij [34]

Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

$\frac{99}{2} (2x+98)=p^3 \\ \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}$

By substitution, we have that $p=33$ and $x=314$ .

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>

3 0

3 years ago