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SSSSS [86.1K]
3 years ago
15

How to order reference list in apa format?

Computers and Technology
1 answer:
Brums [2.3K]3 years ago
5 0
<span>Title. Label this page References, centered in plain text.Spacing. Make sure to double space throughout.Order. List the sources in alphabetical order by the authors' last names. ...<span>Indentation. Do not indent the first line in the citation; however, you must indent any additional lines 5 spaces in the citation.</span></span>
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Henry is creating code In JavaScript to run calculations on extremely small numbers. How can he use MIN_VALUE as validation in t
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In creating code in JavaScript to run calculations on extremely small numbers, MIN_VALUE as validation in the program can be use to check the lowest value JavaScript can handle

Number.MIN_VALUE returns the smallest positive numeric value representable in JavaScript.  It is the number more closer to zero. The value is approximately 5e⁻³²⁴.

Using Number.MIN_VALUE, the value can be printed as follows:

val = Number.MIN_VALUE;

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Therefore, In creating code in JavaScript to run calculations on extremely small numbers, MIN_VALUE as validation in the program can be use to check the lowest value JavaScript can handle.

learn more on JavaScript here: brainly.com/question/13041378?referrer=searchResults

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Read 2 more answers
Write a while loop that prints userNum divided by 2 (integer division) until reaching 1. Follow each number by a space.
Ksenya-84 [330]

Answer:

   while(userNum>=1){

       System.out.print(userNum/2+" ");

       userNum--;

        }

Explanation:

This is implemented in Java programming language. Below is a complete code which prompts a user for the number, receives and stores this number in the variable userNum.

<em>import java.util.Scanner;</em>

<em>public class TestClock {</em>

<em>    public static void main(String[] args) {</em>

<em>    Scanner in = new Scanner (System.in);</em>

<em>        System.out.println("Enter the number");</em>

<em>    int userNum = in.nextInt();</em>

<em>    while(userNum>=1){</em>

<em>        System.out.print(userNum/2+" ");</em>

<em>        userNum--;</em>

<em>         }</em>

<em>    }</em>

<em>}</em>

The condition for the while statement is userNum>=1 and after each iteration we subtract 1 from the value of   userNum until reaching 1 (Hence userNum>=1)

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