Answer:
The packet will take a shorter path through networks 2 and 4
Answer:
Answer below.
Explanation:
You are creating an object of bird "b" with a talon strength of 5 and a beak of 5.
public Hawk(int talon, int beak)
{
super(beak);
talonStrength = talon;
}
Please mark brainliest if this is the answer you were looking for
Please mark brainliest if this is the answer you were looking for
let's say they catch-up to each other after t hour.
so
in t hour distance travelled by Renee
d = speed × time = 50t
in t hour distance travelled by Kim
d = speed × time = 60(t-1) + 0×1 = 60(t-1)
Note: here kim didn't covered any distance in first hour and in rest t-1 hour it travelled all distance
now.as distance travelled by both is same so
60(t-1) = 50t
60t -60 = 50t
adding 60 both sides
60t = 50t+60
subtracting 50t both sides
60t -50t = 50t+60 - 50t
10t = 60
dividing by 10 both sides
t = 60/10 = 6
so in 6 hour both will catch-up to each other
Answer:
Connection-oriented is the method which is implemented in the transport and data link layer. It is basically depend upon the physical connection in the network system.
Transmission control protocol (TCP) is the connection oriented and user datagram protocol (UDP) is the connection less network transport layer. The TCP and UDP both are operate in the internet protocol (IP).
It basically require connection and it can be establish before sending data. This is also known as reliable network connection service. The connection oriented service establish connection between the different connection terminal before sending any data or information. It can easily handle traffic efficiently.
