Answer:a. μ = 9.667 hours
b. σ = 1.972 hours
c. SE = 0.805 hour
Sample size (n) = 6
Sample data (xi) = 10, 8, 9, 7, 11, 13
a. Mean time spent in a week for this course by students:
Sample mean is given by:
Mean time spent in a week per student is 9.667 hours
b. Standard deviation of the time spent in a week for this course by students:
Standard deviation is given by:
c. Standard error of the estimated mean time spent in a week for this course by students:
Standard error is given by:
Answer:
96 pizzas
Step-by-step explanation:
First, we have to determine how many pizza he can make in one minute = 8/15 = 0.533
Convert 3 hours to minutes = 3 x 60 = 180 minutes
The number of pizzas he would make in 3 hours = 180 x 0.533 = 96 pizzas
Answer:
c and d
Step-by-step explanation:
Plug the value of 9 in for y
9=-3x+6
Subtract 6 from both sides
3=-3x
Divide both sides by -3
-1=x
Final answer: x=–1
First problem:
The answer is C because theoretically it should have a 50% of landing
heads but instead it lands heads 56% of the time. Thus this is 6% higher
than 50%. It's not D because there is not specified detail of how the
person got this data so you can assume that the person did a fair
survey/data collection.
Second problem:
So in a data size of 490, 140 of them we trout. This means that 140/490 or 28.57% of the fish are trout. This means that in a sample size of 5000 fish, 5000*0.2857 or 1428.57 are trout.
Third problem:
The Science students seem to have a higher average score because the average score of Math students are:
(32+33+34+34+35+37+39+40+40)/9=36
average score of Science students are:
(41+42+43+43+46+46+47+49+49)/9=45.111
