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Sonbull [250]
3 years ago
11

Can someone help me understand how to solve a two variable equation I am really lost

Mathematics
1 answer:
Llana [10]3 years ago
7 0
Easiest method solving 2 unknowns is Substitution. 
So there will normally be 2(ormore)equations given. 
Say 
X+Y= a
 bX=cY + d 
a b c d are numbers they give
So first we rearrange the first equation
X  = a - Y 
No we substitute this into the 2nd equation so that we can get Y
since we know X = a-Y, 
b(a-Y) = cY + d 
we rearrange and we can find Y for this, it is just Y and numbers
hence finding Y, we sub the value for Y into X = a-Y and we get X also . 

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In a triangle ABC, AD is drawn perpendicular to BC. <br> Prove that AB2 - BD2 = AC2 - CD2.
Finger [1]

Answer:

Given: In triangle ABC , AD is drawn perpendicular to BC.

Since AD is drawn perpendicular to BC, it creates two right triangles: ADB and ADC.

Prove that: AB^2-BD^2 = AC^2-CD^2

Pythagoras triangle for right angle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.

In a right angle triangle ADB;

AD^2+BD^2 = AB^2                 [By Pythagoras theorem]

or

AD^2= AB^2-BD^2                      .......[1]

Now, in right angle triangle ADC;

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or we can write this as;

AD^2= AC^2-CD^2                    ......[2]

Substituting the equation [1] in [2] we get;

AB^2-BD^2 =AC^2-CD^2            hence proved!

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