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SIZIF [17.4K]
3 years ago
6

Ammonia (nh3) is widely used as a fertilizer and in many household cleaners. how much ammonia is produced when 6.64 mol of hydro

gen gas react with an excess of nitrogen gas
Chemistry
1 answer:
olga55 [171]3 years ago
5 0
N₂ + 3H₂ ⇒ 2NH₃

doesnt matterN₂ + 6.64H₂ ⇒ 2NH₃

(6.64H₂/3H₂) x (2NH₃) =4.4266667

rounded to sig figs= 4.43

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Use the following equation to answer question 1-4. Make sure you balance first.
worty [1.4K]
<h3>Answer:</h3>

5.2 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 6HCl + Fe₂O₃ → 2FeCl₃ + 3H₂O

[Given] 10.4 mol HCl

<u>Step 2: Identify Conversions</u>

[RxN] 6 mol HCl = 3 mol H₂O

<u>Step 3: Stoichiometry</u>

  1. Set up:                             \displaystyle 10.4 \ mol \ HCl(\frac{3 \ mol \ H_2O}{6 \ mol \ HCl})
  2. Multiply/Divide:               \displaystyle 5.2 \ mol \ H_2O
4 0
3 years ago
Combustion of 25.0 g of a hydrocarbon produces 86.5 g of co2. what is the empirical formula of the compound?
Step2247 [10]
Combustion is a reaction between a combustible substance and oxygen, to ultimately produce carbon dioxide and water. Reaction between carbon and oxygen would give,

                               C     +     O2      ------>  CO2

Here, we have 86.5 grams of carbon dioxide, CO2, which is a product of combustion. Dividing this mass by the molar mass of CO2, which is 44 grams, we can determine the number of moles of CO2. 

                          <u>     86.5 g CO       </u>   = 1.966 moles CO2
                            44 g CO2/ mole

Considering that CO2 is composed of 1 mole of carbon and 2 moles of oxygen, and that with complete combustion, 1 mole of carbon reacts to produces 1 mole of CO2, we can then determine the mass of the carbon in the hydrocarbon fuel. 

        1.966 moles CO2   x   <u>   1 mole C   </u>    x   <u>   </u><u>12 g C   </u>  = 23.59 g C
                                             1 mole CO2          1 mole C

We were given 25.0 grams of the fuel hydrocarbon. A hydrocarbon is a substance consisting of carbon and hydrogen. To determine the mass of the hydrogen in the fuel, we simply subtract 23.59 grams from 25.0 grams. 


            25.0 g - 23.59 g = 1.41 grams Hydrogen 

To know the number of moles of hydrogen, we divide the mass of the hydrogen in the fuel by the molar mass of hydrogen, which is 1.01 g/mole. Thus, we have 1.396 mole hydrogen. 

To determine the empirical formula, we divide the number of moles carbon by the number of moles hydrogen, and find a factor that would give whole number ratios for the carbon and hydrogen in the fuel, 

Carbon:     <u>  1.966 mol   </u>   = 1.408   x   5 (factor)     = 7
                    1.396 mol

Hydrogen:  <u>  1.396 mol   </u>    = 1.00   x    5 (factor)    = 5
                     1.396 mol

Thus, the empirical formula is C7H5

       
4 0
4 years ago
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Describe bonding in water molecules using the VBT. Show the overlap of hybridised orbitals leading to the formation of H2O molec
Bogdan [553]
Yes I’m going to go ask my mama, she said the answer is 1993629
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3 years ago
Jimmy developed a model to show the difference between pure substances and mixtures
IrinaK [193]
  1. Pure substances cannot be separated into any other kinds of matter, while a mixture is a combination of two or more pure substances.
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<u>Explanation:</u>

  • A matter which cannot be separated into any other kind of matter using the chemical or physical process is called pure substances. A pure substance has the same color, composition, and texture.
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3 years ago
Physical or chemical ?
Artist 52 [7]

Answer:

P,C,P,C,P,C,P,P,C,P

Explanation:

7 0
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