The force due to friction is generally independent of the contact area between the two surfaces. This implies regardless of whether you have two overwhelming objects of a similar mass, where one is half as long and twice as high as the other one, despite everything they experience the equivalent frictional power when you drag them over the ground.
Since water has a density of about 1g/mL, and we are assuming HCl and NaOH are mostly water, the total mass of the 2 solutions is 100 g.
Due to the conservation of mass, the mass of product must equal the total mass of reactant, therefore the final mass must also be 100 g.
Answer: 160 ml
Explanation:
The expression used will be :
where,
= concentration of Ist alcohol solution= 10%
= concentration of 2nd alcohol solution= 55%
= volume of Ist alcohol solution = 200 ml
= volume of 2nd alcohol solution= v ml
= concentration of resulting alcohol solution= 30%
= volume of resulting alcohol solution= (v+200) ml
Now put all the given values in the above law, we get the volume of added.
By solving the terms, we get :
Therefore, the volume of 55% mixture needed to be added to obtain the desired solution is 160 ml.
The answer is:
It will float
