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Bogdan [553]
2 years ago
5

Explain why children should not be forced to choose sides in a divorce situation, provide two responses

Chemistry
1 answer:
ra1l [238]2 years ago
5 0
Children should not be put into the situations such as the one depicted in this given item. They are still to young to weigh in as to which parent will they will be happier with. Also, they will be very much burdened with the idea of splitting parents disallowing them to focus on other things currently going on.
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Water can be formed from the synthesis reaction of hydrogen with oxygen<br><br> PLEASE HELP
Anestetic [448]

Answer:

1.4 mols

4th answer

Explanation:

22. 5 g of O2 in moles = (22.5/32) mols = 0.703 mol

The stoichiometry between O2 and H2O =1: 2

Therefore H2O produced = 2 * 0.703 mols=1.406 mols

8 0
2 years ago
The mass of the atom is found by adding is protons and neutrons the electrical charge of an atom is found by adding the charge i
Hitman42 [59]
When you combine protons and neutrons in the electrical charge they combine to make electricity
3 0
3 years ago
A compound contains 6.0 g of carbon and 1.0 g of hydrogen and has a molar mass of 42.0 g/mol.
makvit [3.9K]

Answer:

%C = 85.71 wt%; %H = 14.29 wt%; Empirical Formula => CH₂; Molecular Formula => C₃H₆

Explanation:

%Composition

Wt C = 6 g

Wt H = 1 g

TTL Wt = 6g + 1g = 7g

%C per 100wt = (6/7)100% = 85.71 wt%

%H per 100wt = (1/7)100% = 14.29 wt % or, %H = 100% - %C = 100% - 85.71% = 14.29 wt% H

What you should know when working empirical formula and molecular formula problems.

Empirical Formula=> <u>smallest</u> whole number ratio of elements in a compound

Molecular Formula => <u>actual</u> whole number ratio of elements in a compound

Empirical Formula Weight x Whole Number Multiple = Molecular Weight

From elemental %composition values given (or, determined as above), the empirical formula type problem follows a very repeatable pattern. This is ...

% => grams => moles => ratio => reduce ratio => empirical ratio

for determination of molecular formula one uses the empirical weight - molecular weight relationship above to determine the whole number multiple for the molecular ratios.

Caution => In some 'textbook' empirical formula problems, the empirical ratio may contain a fraction in the amount of 0.25, 0.50 or 0.75. If such an issue arises, multiply all empirical ratio numbers containing 0.25 and/or 0.75 by '4'  to get the empirical ratio and multiply all empirical ration numbers containing 0.50 by '2' to get the final empirical ratio.

This problem:

Empirical Formula:

Using the % per 100wt values in part 'a' ...

              %     =>         grams                 =>                 moles

%C => 85.71% => 85.71 g* / 100 g Cpd => (85.71 / 12) = 7.14 mol C

%H => 14.29% => 14.29 g / 100 g Cpd => (14.29 / 1) = 14.29 mol H

=> Set up mole Ratio and Reduce to Empirical Ratio:

mole ratio C:H =>  7.14 : 14.29

<u>To reduce mole values to the smallest whole number ratio,  divide all mole values by the smaller mole value of the set.</u>

=> 7.14/7.14 : 14.29/7.14 => Empirical Ration=> 1 : 2

∴ Empirical Formula => CH₂

Molecular Formula:

(Empirical Formula Wt)·N = Molecular Wt => N = Molecular Wt / Empirical Wt

N = 42 / 14 = 3 => multiply subscripts of empirical formula by '3'.

Therefore, the molecular formula is C₃H₆

3 0
2 years ago
A small piece of hot metal is placed in cooler water. The metal is left in the water
scoundrel [369]

Answer: The amount of energy lost by the metal is equal to the amount of energy gained by the water

Explanation:

5 0
2 years ago
How many grams are in 5 mols of KOH​
elena55 [62]

Answer:

0.08911760029829444

Explanation:

hop that this what you wanted

8 0
2 years ago
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