Answer:
B. CaCl + LiCO3 yields CaCO3 + LiCl is not correct
It should be CaCl2 + Li2CO3 → 2LiCl + CaCO3
Explanation:
For a reaction to be double displacement reaction there are two things we need to look for
1) There must be an interchange of the group of ions
2) The reactants must dissolve in water to release ions
A. 2RbNO3 + BeF2 yields Be(NO3)2 + 2RbF
2Rb+ + NO3- + Be^2+ + 2F- → Be(NO₃)₂ + 2RbF
This is correct
B. CaCl + LiCO3 yields CaCO3 + LiCl
This is not correct
The correct equation is:
CaCl2 + Li2CO3 → Ca2+ + 2Cl- + 2Li+ + CO3^2- → 2LiCl + CaCO3
C. Na3PO4 + 3KOH yields 3NaOH + K3PO4
3Na+ + PO4^3- + 3K+ + 3OH- → 3NaOH + K3PO4
This is correct
D. 2MgI2 + Mn(SO3)2 yields 2MgSO3 + MnI4
2Mg^2+ + 4I- + Mn^4+ + 2SO3^2- → 2 MgSO3 + MnI4
This is correct
Answer: what would swimming in mathane lake on titan feel like.
Explanation:
Using hydrogen and Lindlar catalyst the triple bond will be hydrogenated to a double one with a cis conformation.
C. the substance only changed form or appearance
the substance changes at a chemical level, not just in appearance
Answer:
Oxidation number of each atom in sodium hydrogen carbonate ( NaHCO3) are
Na = +1
H = +1
C = +4
O = -2
Explanation:
Let's pick the first atom
NaHCO3
find oxidation number of Na
Na + 1 +4 + 3(-2) = 0( because there is no charge)
Na + 5 - 6 = 0
Na = 6 -5
Na = +1
Always put the sign
Find the oxidation number of H in NaHCO3
+1 + H + 4 + 3(-2) = 0.
H + 1 + 4 + 3(-2) = 0
H + 5 -6 = 0
H = 6 -5
H = +1
Find the oxidation number of C In NaHCO3
+1 +1 +C + 3(-2) = 0
C + 1+1-6 = 0
C +2 - 6= 0
C = 6 -2
C = +4
Find the oxidation number of O in NaHCO3
+1 + 1 + 4 + 3(O) = 0
6 + 3 (O) = 0
3(O) = -6
Divide through by 3 to get O
3(O) / 3 = -6 / 3
O = -6/3
O = -2
