0.015 M HNO3 = 0.015 M H3O+ pH = -log(0.015) = 1.82 [OH -] = 1.0 x 10 -14/0.015 M = 6.7 x 10 13 Check: HNO3 is a strong acid, so we expect the pH to be low and the [OH ] to be small

8 0

3 years ago

Which number should go in the blank? - H₂ + O2 -> 2H₂O O 2 3 1

nydimaria [60]

2 is the number as you need to balance the equation

8 0

3 years ago

calculate the molarity of 0.57 moles NaHCO3 in 61.2 mL of solution. Report your answer 4 places after the decimal don’t forget t

VARVARA [1.3K]

Answer:

The correct response is "9.313 M".

Explanation:

According to the question, the values are:

Moles of solute,

= 0.57 moles

Liters of solution,

= 61.2 mL

or,

= 0.0612 L

Now,

The molarity will be:

= $\frac{Moles \ of \ solute}{Liters \ of \ solution}$

On putting the given the values in the above formula, we get

= $\frac{0.57}{0.0612}$

= $9.313 \ M$

3 0

3 years ago

Which of the following is the best definition for volume

UNO [17]

Answer:

Explanation:

I hope that helps!!! it kinda gave you the answer though

7 0

3 years ago

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