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goldenfox [79]
3 years ago
11

Use the graph representing bacteria decay two estimate the domain of the function and sulfur the average rate of change across t

he domain.

Mathematics
1 answer:
gregori [183]3 years ago
3 0
<h3>Answer: Choice C</h3>

\text{Domain}: 0 \le x \le 55 and \text{Average rate of change over domain} = -1.45 (average rate of change is approximate)

=========================================================

The domain is the set of allowed x inputs of the function. The smallest x value shown is x = 0, which is from the point (0,80). The largest x value possible is x = 55 from the point (55,0)

The domain is the set of all values between 0 and 55, including both endpoints. Therefore, we get a domain of 0 \le x \le 55

Compute the slope of the line through (0,80) and (55,0) to find the average rate of change over the entire function domain.

m = (y2 - y1)/(x2 - x1)

m = (0 - 80)/(55 - 0)

m = -80/55

m = -1.45 approximately

The slope of the line through (0,80) and (55,0) is approximately -1.45, which is also the average rate of change over the entire domain.

Side note: the negative slope or negative rate of change indicates we are going downhill ultimately as we move from left to right.

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Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
2 years ago
How can the iready test is a real test?
Leona [35]
It isn't a real test. I do believe it helps you with your grade and the classes you'll take next year.
3 0
3 years ago
There are 120 five-digit numbers that can be made from the digits 1, 2, 3, 4, 5 if each digit is used once in the number. That s
Harman [31]

Answer:

41235

Step-by-step explanation:

There are 120 five-digit numbers that can be made from the digits 1, 2, 3, 4, 5 if each digit is used once in the number,

The total number of times where each number will occur or be at first place is calculated as:

4! = 4 × 3 × 2 × 1

= 24

Hence,

24th number = The last number where 1 is at first place

We can write this out as:

12345

12354

12435

12453

12534

12543

13245

13254

13425

13452

13524

13542 e.t.c.

48th number = The last number where 2 is at first place

72nd place = The last number where 3 is at first place.

This means, the 73rd number is the first number where 4 is at first place.

Therefore, the 73rd number based on pattern is 41235

8 0
3 years ago
Help me what is 6x4 and 3x6
Taya2010 [7]

6 x 4= 24

3 x 6= 18

Hope this helps!!

7 0
3 years ago
Subtract. Your answer should be a polynomial in standard form. a (4r ^ 2 - 3r + 2) - (- r ^ 2 - 3r) =
blsea [12.9K]

Answer:5r2+2

Step-by-step explanation:

Distribute the Negative Sign:

=4r2−3r+2+−1(−r2−3r)

=4r2+−3r+2+−1(−r2)+−1(−3r)

=4r2+−3r+2+r2+3r

Combine Like Terms:

=4r2+−3r+2+r2+3r

=(4r2+r2)+(−3r+3r)+(2)

=5r2+2

6 0
3 years ago
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